我有一些地址需要使用Google的Geocode api转换为纬度/经度。我正在将地址和城市输入Google Geocode URL,这形成了正确的连接URL。
基本上,我希望能够使用for循环创建多个NSURLConnection请求,并返回多个响应。
-(void)setString{
for (int i = 0; i < [businessArray count]; i ++)
{
NSString *address = [addressArray objectAtIndex:0];
NSString *city = [locationDict valueForKey:@"city"];
NSString *geocodeURL = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?address=%@,+%@,&sensor=true", address, city];
geocodeURL = [geocodeURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:geocodeURL]
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:10];
NSLog(@"%@", request);
geoCodeConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self startImmediately:YES];
if (geoCodeConnection)
{
responseData = [NSMutableData data];
connectionIsActive = YES;
NSLog(@"connection active");
} else {
NSLog(@"connection failed");
connectionIsActive = NO;
}
}
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
NSError *jsonError = nil;
SBJsonParser *json = [[SBJsonParser alloc] init];
NSDictionary *parsedJSON = [json objectWithString:responseString error:&jsonError];
NSString *lat= [[[[parsedJSON valueForKey:@"results"] valueForKey:@"geometry"] valueForKey:@"location"] valueForKey:@"lat"];
NSString *lng= [[[[parsedJSON valueForKey:@"results"] valueForKey:@"geometry"] valueForKey:@"location"] valueForKey:@"lng"];
NSLog(@"lat = %@ long= %@", lat, lng);
connectionIsActive = NO;
[geoCodeLatArray addObject:lat];
[geoCodeLngArray addObject:lng];
NSLog(@"geoCodeArrayLat: %@", geoCodeLatArray);
}
现在,该代码仅返回最后一个地址的经纬度。如何使用JSON发送乘法请求并返回乘法响应?
最佳答案
试试这个,我正在用这个,
for(int i=0;i< businessArray.count;i++)
{
NSString *address = [addressArray objectAtIndex:i];
NSString *city = [locationDict valueForKey:@"city"];
NSString *address = [NSString stringWithFormat:@"%@,%@", address, city];
CLLocationCoordinate2D location = [self geoCodeUsingAddress:address];
// then here store the location.latitude in lat array and location.longitude in long array.
}
- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSDictionary *googleResponse = [[NSString stringWithContentsOfURL: [NSURL URLWithString: req] encoding: NSUTF8StringEncoding error: NULL] JSONValue];
NSDictionary *resultsDict = [googleResponse valueForKey: @"results"];
NSDictionary *geometryDict = [resultsDict valueForKey: @"geometry"];
NSDictionary *locationDict = [geometryDict valueForKey: @"location"];
NSArray *latArray = [locationDict valueForKey: @"lat"];
NSString *latString = [latArray lastObject];
NSArray *lngArray = [locationDict valueForKey: @"lng"];
NSString *lngString = [lngArray lastObject];
CLLocationCoordinate2D location;
location.latitude = [latString doubleValue];
location.longitude = [lngString doubleValue];
return location;
}
更新到以上功能:
- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
double latitude = 0, longitude = 0;
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
if (result) {
NSScanner *scanner = [NSScanner scannerWithString:result];
if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil]) {
[scanner scanDouble:&latitude];
if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil]) {
[scanner scanDouble:&longitude];
}
}
}
CLLocationCoordinate2D location;
location.latitude = latitude;
location.longitude = longitude;
return location;
}
这对我有用。