我正在使用改进来集成我的web服务,我不知道如何使用post请求将json对象发送到服务器。我现在卡住了,这是我的代码:
活动:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Retrofit retrofit = new Retrofit.Builder().baseUrl(url).
addConverterFactory(GsonConverterFactory.create()).build();
PostInterface service = retrofit.create(PostInterface.class);
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("email", "[email protected]");
jsonObject.put("password", "1234");
} catch (JSONException e) {
e.printStackTrace();
}
final String result = jsonObject.toString();
}
后界面:
public interface PostInterface {
@POST("User/DoctorLogin")
Call<String> getStringScalar(@Body String body);
}
请求JSON:-
{
"email":"[email protected]",
"password":"1234"
}
响应JSON:-
{
"error": false,
"message": "User Login Successfully",
"doctorid": 42,
"active": true
}
最佳答案
在格雷德使用这些
compile 'com.squareup.retrofit2:retrofit:2.3.0'
compile 'com.squareup.retrofit2:converter-gson:2.3.0'
compile 'com.squareup.retrofit2:converter-scalars:2.3.0'
使用这两个pojo类……。
登录数据类
public class LoginData {
private String email;
private String password;
public LoginData(String email, String password) {
this.email = email;
this.password = password;
}
/**
*
* @return
* The email
*/
public String getEmail() {
return email;
}
/**
*
* @param email
* The email
*/
public void setEmail(String email) {
this.email = email;
}
/**
*
* @return
* The password
*/
public String getPassword() {
return password;
}
/**
*
* @param password
* The password
*/
public void setPassword(String password) {
this.password = password;
}
}
loginResult.Class类
public class LoginResult {
private Boolean error;
private String message;
private Integer doctorid;
private Boolean active;
/**
*
* @return
* The error
*/
public Boolean getError() {
return error;
}
/**
*
* @param error
* The error
*/
public void setError(Boolean error) {
this.error = error;
}
/**
*
* @return
* The message
*/
public String getMessage() {
return message;
}
/**
*
* @param message
* The message
*/
public void setMessage(String message) {
this.message = message;
}
/**
*
* @return
* The doctorid
*/
public Integer getDoctorid() {
return doctorid;
}
/**
*
* @param doctorid
* The doctorid
*/
public void setDoctorid(Integer doctorid) {
this.doctorid = doctorid;
}
/**
*
* @return
* The active
*/
public Boolean getActive() {
return active;
}
/**
*
* @param active
* The active
*/
public void setActive(Boolean active) {
this.active = active;
}
}
像这样使用api
public interface RetrofitInterface {
@POST("User/DoctorLogin")
Call<LoginResult> getStringScalar(@Body LoginData body);
}
像这样打电话…
Retrofit retrofit = new Retrofit.Builder()
.baseUrl("Your domain URL here")
.addConverterFactory(ScalarsConverterFactory.create())
.addConverterFactory(GsonConverterFactory.create())
.build();
RetrofitInterface service = retrofit.create(RetrofitInterface .class);
Call<LoginResult> call=service.getStringScalar(new LoginData(email,password));
call.enqueue(new Callback<LoginResult>() {
@Override
public void onResponse(Call<LoginResult> call, Response<LoginResult> response) {
//response.body() have your LoginResult fields and methods (example you have to access error then try like this response.body().getError() )
}
@Override
public void onFailure(Call<LoginResult> call, Throwable t) {
//for getting error in network put here Toast, so get the error on network
}
});
编辑:
把这个放在
success()
里面…if(response.body().getError()){
Toast.makeText(getBaseContext(),response.body().getMessage(),Toast.LENGTH_SHORT).show();
}else {
//response.body() have your LoginResult fields and methods (example you have to access error then try like this response.body().getError() )
String msg = response.body().getMessage();
int docId = response.body().getDoctorid();
boolean error = response.body().getError();
boolean activie = response.body().getActive()();
}
注意:-总是使用pojo类,它删除了改造中的json数据解析。