java - txt文件输入错误Java

我遇到了错误

Exception in thread "main" java.lang.NumberFormatException: For input string: "scores.txt"
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1222)
at java.lang.Double.parseDouble(Double.java:510)
at ExamAverage.main(ExamAverage.java:30)
 C:\Users\Peter\AppData\Local\Temp\codecomp5461808896109186034.xml:312: Java returned: 1

对于下面列出的我的代码，此错误是什么意思？我正在尝试从给定的文本文件路径一行一行地输出，并以某种格式输出。

       import java.io.FileReader;
      import java.io.FileNotFoundException;
      import java.util.Scanner;
      import java.io.PrintWriter;

      public class ExamAverage
     {

     public static void main(String[] args)
  throws FileNotFoundException
  {
  String inputFileName = "scores.txt";
  String outputFileName = "examScoreAverage.txt";
  Scanner console = new Scanner(System.in);
  Scanner in = new Scanner(inputFileName);
  PrintWriter out = new PrintWriter(outputFileName);
  int TestNumber = 1;
  double totalPoints = 0;
  double avg = 0;
  double test = 0;

    while (in.hasNextLine())
    {
       String line = in.nextLine();
          test = Double.parseDouble(line);
       out.println("Score" + TestNumber + " : " + test);
       totalPoints += test;
       TestNumber++;
    }
       avg = totalPoints/TestNumber;
       out.println("Number of scores read: " + TestNumber );
       out.println("Average Score " + avg );
   in.close();
out.close();

}
}

最佳答案

http://download.oracle.com/javase/6/docs/api/java/util/Scanner.html

看来您认为可以将文件名传递给Scanner并打开它。
Scanner的构造函数没有采用您认为的方式将文件名作为参数。您所拥有的是一台正在扫描String“ scores.txt”的扫描仪

JavaDocs向您展示如何正确使用Scanner类来读取文件：

Scanner in = new Scanner(new File(inputFileName));

关于java - txt文件输入错误Java，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/7989334/