我正在研究这个非常简单的方法,我知道我已经很接近完成它了,但是我缺少一个细节。感谢您的帮助。谢谢。
/**
Gets the first letter in this string.
@return the FIRST LETTER, or "" if there are no letters.
add1=AD3F add2=EF4G result=32SFB (BUT THESE ARE RANDOM ONLY INTS AND CHARS)
*/
public String firstLetter()
{
String line = add1+add2+result;
for(int i=0; i<line.length(); i++){
char ch=new Character(line.charAt(i));
if(Character.isLetter(ch)){
System.out.println("This is the first letter"+ch);
return ch;
}
else
System.out.println("No it is not a character: "+ch);
return "";
}
最佳答案
您需要将else
代码移到循环外,以便仅在测试所有字符后才执行:
public class FirstLetter
{
public static void main(String[] args)
{
System.out.println(firstLetter());
}
public static String firstLetter()
{
String line = "AD3F" + "EF4G" + "32SFB";
for (int i = 0; i < line.length(); i++)
{
char ch = line.charAt(i);
if (Character.isLetter(ch))
{
System.out.println("This is the first letter: " + ch);
return Character.toString(ch);
}
}
System.out.println("No character found");
return "";
}
}
当您清楚地格式化代码时,这种问题更加明显。
我将返回类型保留为原始的
String
,但也请参阅乔恩·斯凯特(Jon Skeet)关于将其更改为char
的评论。关于java - 从字符串中获取字母的第一个实例,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/9447947/