所以我有这段代码:
Parse.Cloud.define("apiCall", function(request, response) {
return Parse.Cloud.httpRequest({
// API call 1
}).catch(function(error) {
/// Only perform this if the first call fails
// Return valid json here, to mock the Parse.Cloud.httpRequest below
return Parse.Promise.as({"data": "this is an expected JSON"});
return Parse.Cloud.httpRequest({
// API call 2
});
}).then(
function(httpResponse) {
/// This should perform after call 1, or call 2 if call 1 failed
return Parse.Cloud.httpRequest({
// API call 3
});
}
).catch(
function(error) {
console.log('FAIL');
return response.error(error);
}
);
});
我希望即使呼叫1失败也要执行呼叫3,但显然不会,它执行第一个
catch
块,但随后执行最后一个catch
块。我以为我在catch
块中返回新的诺言时正确捕获了错误? 最佳答案
长话短说,每个Promise链应该只包含一个捕获块。
您可以使用async / await块重构代码,如下所示:
Parse.Cloud.define("apiCall", async function(request, response) {
let response = null;
try {
response = await Parse.Cloud.httpRequest({
// API call 1
})
} catch (error) {
console.log({"data": "this is an expected JSON"});
response = Parse.Cloud.httpRequest({
// API call 2
});
}
try {
// Use response variable here
let response2 = Parse.Cloud.httpRequest({
// API call 3
});
return response2;
} catch (error) {
console.log('FAIL');
return response.error(error);
}
});
如果您想坚持Promise链,也可以执行以下操作:
Parse.Cloud.define("apiCall", function(request, response) {
return new Promise((resolve, reject) => {
Parse.Cloud.httpRequest({
// API call 1
})
.then(function (data) {
resolve(data);
})
.catch(function(error) {
/// Only perform this if the first call fails
// Return valid json here, to mock the Parse.Cloud.httpRequest below
console.log({"data": "this is an expected JSON"});
Parse.Cloud.httpRequest({
// API call 2
})
.then(function (data) {
resolve(data);
})
.catch(function (error) {
reject(error);
})
})
}).then(
function(httpResponse) {
/// This should perform after call 1, or call 2 if call 1 failed
return Parse.Cloud.httpRequest({
// API call 3
});
}
).catch(
function(error) {
console.log('FAIL');
return response.error(error);
}
);
});
关于javascript - 为什么这个 promise 不会转到下一个“那么”?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/49047907/