我正在尝试使用Xstream从XML文件读取。我遇到的奇怪问题是,当我列出用户列表时,它会正确读取第一个用户,但是会尝试将第二个用户存储为第一个用户的成员变量!我有这个XML文件:
<data>
<users>
<user>
<username>test1</username>
<password>test1</password>
<firstname>Test</firstname>
<lastname>One</lastname>
<email>test1@gmail.com</email>
<indexedrecords>0</indexedrecords>
</user>
<user>
<username>test2</username>
<password>test2</password>
<firstname>Test</firstname>
<lastname>Two</lastname>
<email>test2@gmail.com</email>
<indexedrecords>0</indexedrecords>
</user>
</users>
.... There are other tags here, but they're not causing an issue (yet).
</data>
Xstream阅读器的代码:
XStream xstream = new XStream(new StaxDriver());
xstream.addImplicitCollection(Model.class, "users", User.class);
@SuppressWarnings("rawtypes")
Class[] classes = new Class[2];
classes[0] = Model.class;
classes[1] = User.class;
xstream.processAnnotations(classes);
String xml = "";//The XML is really stored here, and it does work correctly
xstream.fromXML(xml);
和班级本身。模型:
@XStreamAlias("data")
public class Model {
@XStreamImplicit
public static List<User> users;
//Other stuff
}
用户:
@XStreamAlias("user")
public class User implements ModelItem{
private String username;
private String password;
@XStreamAlias("firstname")
private String firstName;
@XStreamAlias("lastname")
private String lastName;
private String email;
@XStreamAlias("indexedrecords")
private int recordsIndexed;
}
例外(原谅
[java]
-正在使用ANT运行): [java] Exception in thread "main" com.thoughtworks.xstream.converters.ConversionException: Element user of type shared.model.User is not defined as field in type shared.model.User
[java] ---- Debugging information ----
[java] class : shared.model.User
[java] required-type : shared.model.User
[java] converter-type : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
[java] path : /data/users/user
[java] line number : 19
[java] class[1] : indexer.shared.model.Model
[java] version : null
[java] -------------------------------
[java] at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.writeValueToImplicitCollection(AbstractReflectionConverter.java:403)
[java] at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.doUnmarshal(AbstractReflectionConverter.java:334)
[java] at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.unmarshal(AbstractReflectionConverter.java:234)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convert(TreeUnmarshaller.java:72)
[java] at com.thoughtworks.xstream.core.AbstractReferenceUnmarshaller.convert(AbstractReferenceUnmarshaller.java:65)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:66)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:50)
[java] at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.doUnmarshal(AbstractReflectionConverter.java:322)
[java] at com.thoughtworks.xstream.converters.reflection.AbstractReflectionConverter.unmarshal(AbstractReflectionConverter.java:234)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convert(TreeUnmarshaller.java:72)
[java] at com.thoughtworks.xstream.core.AbstractReferenceUnmarshaller.convert(AbstractReferenceUnmarshaller.java:65)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:66)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.convertAnother(TreeUnmarshaller.java:50)
[java] at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:134)
[java] at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32)
[java] at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1052)
[java] at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1036)
[java] at com.thoughtworks.xstream.XStream.fromXML(XStream.java:912)
[java] at com.thoughtworks.xstream.XStream.fromXML(XStream.java:903)
[java] at importer.Importer.importXml(Importer.java:77)
[java] at importer.Importer.main(Importer.java:45)
为什么Xstream试图将第二个
User
作为变量存储在第一个User
内?答案编辑:有两个问题,都在迈克尔的答案中解决。
1)我的意思是隐式集合(两次!),我不应该这样做,因为XML显式声明了
users
列表。2)我在
Model
类中的变量是静态的。目前尚不清楚为什么会导致错误,但是确实会导致错误。 最佳答案
在用户列表之前的@XStreamImplicit
注释告诉XStream XML将不会有一个标记用户的标签,而是所有被称为用户的标签都应该存储在用户列表中。
从XML中删除users
或从变量声明中删除@XStreamImplicit
批注。
其他变化
您还需要删除对xstream.addImplicitCollection(Model.class, "users", User.class);
的调用,因为这样做与@XStreamImplicit
类似。
修复隐式函数后遇到的另一个问题是由Model类中的users变量声明为static引起的。由于它是静态的,因此不会被视为序列化的一部分。