如果结果等于NaN或-infinity,则我无法找出一种捕捉或下达程序的方法。
每当我在程序中输入0时,都会得到NaN和-Infinity的结果。
我面临的问题是x1和x2是双精度类型,显然不能与String类型进行比较。任何帮助将非常感激。
public class Exercise {
public static void main(String[] args){
double x1 = 0;
double x2 = 0;
Scanner scanner = new Scanner(System.in);
System.out.println("Feed me with a, b and c");
try{
double a = scanner.nextDouble();
double b = scanner.nextDouble();
double c = scanner.nextDouble();
scanner.close();
double discriminant = (b * b) - 4 * (a * c);
if (discriminant > 0){
x1 = (-b + Math.sqrt(discriminant)) / (2 * a);
x2 = (-b - Math.sqrt(discriminant)) / (2 * a);
System.out.println("The dish of yours has two components " + x1
+ " and " + x2);
}
if (discriminant == 0){
x1 = -b / (2 * a);
System.out.println("The dish of yours has two identical
components " + x1 +" and " + x1);
}
if (discriminant < 0){
System.out.println("The dish of yours doesn't have any
component");
}
}
catch (InputMismatchException e) {
System.out.println("I can't digest letters");
}
catch (Exception e) {
System.out.println("This is inedible");
}
}
}
最佳答案
您可以通过执行以下操作来检查NaN
:
if (Double.isNaN(yourResult)) { ... }
通过执行以下操作来实现无穷大:
if (Double.isInfinite(yourResult)) { ... }
永远不要使用
==
检查NaN
,因为NaN
被认为不等于NaN
!或者,您可以仅检查
a
是否为0。因为这可能是Infinity和NaN出现的唯一情况。如果是这样,请说“我的菜在哪里?”之类的话。 :)另外,我只是尝试给出
Nan NaN NaN
而它什么也不输出。考虑检查a,b和c是否也是NaN或Infinities。 :)