我正在尝试使用来自此SO问题Check for x consecutive days - given timestamps in database的查询来计算用户提交活动的连续天数,即3天,5天,7天等。

查询是:

SELECT IF(COUNT(1) > 0, 1, 0) AS has_consec
FROM
(
SELECT *
FROM
(
    SELECT IF(b.dateAdded IS NULL, @val:=@val+1, @val) AS consec_set
    FROM activity a
    CROSS JOIN (SELECT @val:=0) var_init
    LEFT JOIN activity b ON
        a.userID = b.userID AND
        a.dateAdded = b.dateAdded + INTERVAL 1 DAY
    WHERE a.userID = 1
) a
GROUP BY a.consec_set
HAVING COUNT(1) >= 3
) a


当日期字段不是dateTime时,该代码可以很好地工作,但是如何修改代码以忽略dateTime的时间部分?我尝试使用DATE(dateAdded),但是没有用。

我的数据如下:

userID  dateAdded
1       2016-07-01 17:01:56
1       2016-07-02 12:45:49
1       2016-07-03 13:06:27
1       2016-07-04 12:51:10
1       2016-07-05 15:51:10
2       2016-07-06 16:51:10
2       2016-07-07 11:51:10
1       2016-07-08 11:26:38


谢谢

最佳答案

dateAdded字段强制转换为Date

请尝试一下,让我知道它是否解决了该问题:

SELECT IF(COUNT(1) > 0, 1, 0) AS has_consec
FROM
(
SELECT *
FROM
(
    SELECT IF(b.dateAdded IS NULL, @val:=@val+1, @val) AS consec_set
    FROM activity a
    CROSS JOIN (SELECT @val:=0) var_init
    LEFT JOIN activity b ON
        a.userID = b.userID AND
        DATE(a.dateAdded) = DATE(b.dateAdded) + INTERVAL 1 DAY
    WHERE a.userID = 1
) a
GROUP BY a.consec_set
HAVING COUNT(1) >= 3
) a;


注意:仅当它们具有相同的timestamp时,使用time (hh:mm:ss)将返回正确的输出。

关于mysql - 从MySQL数据连续获取3天,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/38319544/

10-13 08:49
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