我试图遍历三个数据框以发现它们之间的差异。我有一个包含所有内容的主数据框架,还有两个包含其他部分主数据框架的数据框架。我正在尝试编写python代码来识别其他两个文件中缺少的内容。主文件如下所示:
ID Name
1 Mike
2 Dani
3 Scott
4 Josh
5 Nate
6 Sandy
第二个数据帧如下所示:
ID Name
1 Mike
2 Dani
3 Scott
6 Sandy
第三个数据帧如下所示:
ID Name
1 Mike
2 Dani
3 Scott
4 Josh
5 Nate
这样就会有两个输出数据帧。所需的输出看起来像下面的第二个数据帧:
ID Name
4 Josh
5 Nate
第三个数据帧的所需输出如下所示:
ID Name
6 Sandy
我在Google上找不到任何类似的内容。我尝试了这个:
for i in second['ID'], third['ID']:
if i not in master['ID']:
print(i)
它返回主文件中的所有数据。
另外,如果我尝试此代码:
import pandas as pd
names = ["Mike", "Dani", "Scott", "Josh", "Nate", "Sandy"]
ids = [1, 2, 3, 4, 5, 6]
master = pd.DataFrame({"ID": ids, "Name": names})
# print(master)
names_second = ["Mike", "Dani", "Scott", "Sandy"]
ids_second = [1, 2, 3, 6]
second = pd.DataFrame({"ID": ids_second, "Name": names_second})
# print(second)
names_third = ["Mike", "Dani", "Scott", "Josh", "Nate"]
ids_third = [1, 2, 3, 4, 5]
third = pd.DataFrame({"ID": ids_third, "Name": names_third})
# print(third)
for i in master['ID']:
if i not in second["ID"]:
print("NOT IN SECOND", i)
if i not in third["ID"]:
print("NOT IN THIRD", i)
输出::
NOT IN SECOND 4
NOT IN SECOND 5
NOT IN THIRD 5
NOT IN SECOND 6
NOT IN THIRD 6
为什么说
NOT IN SECOND 6
和NOT IN THIRD 5
?有什么建议吗?提前致谢。
最佳答案
您可以尝试将.isin
与~
一起使用以过滤dataframes
。要与第二个进行比较,您可以使用master[~master.ID.isin(second.ID)]
和类似的作为第三个:
cmp_master_second, cmp_master_third = master[~master.ID.isin(second.ID)], master[~master.ID.isin(third.ID)]
print(cmp_master_second)
print('\n-------- Seperate dataframes -----------\n')
print(cmp_master_third)
结果:
Name
ID
4 Josh
5 Nate
-------- Seperate dataframes -----------
Name
ID
6 Sandy
关于python - 遍历不同的数据框,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/50959624/