我正在使用UserDefaults来存储和检索我的数据,但是我不知道为什么当我执行展开segue时,我的userdefaults数据不能传递到下一个视图控制器,但是如果我执行常规的push segue,则我的userdefaults数据可以可以在下一个viewcontroller中看到。

附注:只有self.performSegue(withIdentifier: "unwindSegue", sender: nil)是unwindSegue。

FirstViewController

@IBAction func Button1(_ sender: Any) {
    var i: Int = 0
    let randomNumber = arc4random_uniform(3) + 1
    i = Int(randomNumber)

    let alert = AlertController(title: "Congratualations", message: "You earned \(i) tokens!", preferredStyle: .alert)
    alert.setTitleImage(UIImage(named: "token"))
    // Add actions
            alert.addAction(UIAlertAction(title: "Let's See!", style: UIAlertActionStyle.default, handler: { (action) in
                var returnValue: Int = UserDefaults.standard.integer(forKey: "tokens")
                returnValue = returnValue + i;
                UserDefaults.standard.set(returnValue, forKey:"tokens")
                self.performSegue(withIdentifier: "unwindSegue", sender: nil)
                }))
        if (returnValue != 30){
            alert.addAction(UIAlertAction(title: "Continue Playing", style: UIAlertActionStyle.default, handler:    { (action) in
                var returnValue: Int = UserDefaults.standard.integer(forKey: "tokens")
                returnValue = returnValue + i;
                UserDefaults.standard.set(returnValue, forKey:"tokens")
                self.performSegue(withIdentifier: "continue", sender: self)
                }))
        }
    self.present(alert, animated: true, completion: nil)
}

SecondViewController
import UIKit

class TokenController: UIViewController {
    @IBOutlet var tokens: UILabel!
    @IBOutlet var minus1: UIButton!
    @IBOutlet var minus2: UIButton!
    var returnValue: Int = UserDefaults.standard.integer(forKey: "tokens")

    override func viewDidLoad() {
        super.viewDidLoad()
        tokens.text = "x\(returnValue)"
    }

@IBAction func unwindSegue(_ sender: UIStoryboardSegue) {
}

ios - unwindSegue无法传递数据(Swift-Xcode)-LMLPHP
ios - unwindSegue无法传递数据(Swift-Xcode)-LMLPHP

最佳答案

@Kinja请参考此URL以使用unse segue

点击这里:-Perform action when segue is closed

关于ios - unwindSegue无法传递数据(Swift-Xcode),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/48519844/

10-10 21:14
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