我想做一个与乡村和城镇相关的选择
国家数据是
var arr_country=[
{"id": 100,"name":"台北市"},
{"id": 200,"name":"新北市"},
{"id": 300,"name":"桃園市"},
{"id": 400,"name":"新竹縣"},
{"id": 500,"name":"台中市"}
]
var arr_town=[
{"id": 10011,"name":"中正區"},
{"id": 10022,"name":"信義區"},
{"id": 20011,"name":"板橋區"},
{"id": 20022,"name":"永和區"},
{"id": 30011,"name":"龜山區"},
{"id": 30022,"name":"八德區"},
{"id": 40011,"name":"新豐鄉"},
{"id": 40022,"name":"湖口區"},
{"id": 50011,"name":"北屯區"},
{"id": 50022,"name":"大雅區"}
]
HTML代码是
<select id="country"></select>
<select id="town"></select>
我无法更改JSON数据格式
这两个数据的关系是
国家id=XXX
城镇id=XXXOO
如何将匹配数组筛选为动态插入选项以进行城镇选择
我试着写些剧本
var counties_option = '';
for (var i = 0; i < arr_country.length; i++) {
counties_option += '<option value="' + arr_country[i].id + '">' + arr_country[i].name + '</option>';
}
$('#country')
.append(counties_option)
.on('change',function(){
$('#town').empty();
var selected_counties=this.value
var filtered_arr=arr_town.filter(function(item){
return item.id==selected_counties;
});
var town_option = '';
for (var j = 0; j < filtered_arr.length; j++) {
town_option += '<option value="' + filtered_arr[j].id + '">' + filtered_arr[j].name + '</option>';
}
$('#town').append(town_option)}).trigger('change');
这是我的jsFiddle实践=>jsFiddle practice
最佳答案
像这样更新你的函数
var filtered_arr=arr_town.filter(function(item){
return item.id.toString().substring(0,3)==selected_counties;
});
这是有效的,我也更新了您的jsfiddle。http://jsfiddle.net/nmongiya/0dj6uaph/
关于javascript - 按部分数据过滤数组,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/52713095/