表:contactcompany和具有自定义透视属性的关系表company_contact (company_id, contact_id, is_main)
公司和联系人有多对多的关系(在两种型号上都是belongsTo)。
检索公司联系人时的预期输出:

{
    "data": [
        {
            "id": 1,
            "name": "JohnDoe",
            "is_main": false
        },
        {
            "id": 2,
            "name": "JaneDoe",
            "is_main": true
        }
    ]
}

使用?include=companies检索联系人列表时的预期输出:
{
    "data": [
        {
            "id": 1,
            "name": "John Doe",
            "companies": {
                "data": [
                    {
                        "id": 501,
                        "name": "My Company",
                        "is_main": true
                    },
                    {
                        "id": 745,
                        "name": "Another Company",
                        "is_main": false
                    }
                ]
            }
        },
        {
            "id": 2,
            "name": "Jane Doe",
            "companies": {
                "data": [
                    {
                        "id": 999,
                        "name": "Some Company",
                        "is_main": true
                    }
                ]
            }
        }
    ]
}

添加透视表属性的最佳方法是什么?如果设置了属性,那么在company transformer上添加is_main似乎不是很干净。
对于第一个例子,我正在考虑使用参数?include=company_relationship:company_id(1),比如:
public function includeCompanyRelationship(Contact $contact, ParamBag $params) {
    // .. retrieve the pivot table data here
    $is_main = $company->is_main;

    // but now I would need another transformer, when what I actually want is to push the value on the main array (same level)

    return $this->item(??, ??);
}

我了解如何检索pivot数据(相关:Laravel 5.1 - pivot table between three tables, better option?),但不是将其添加到https://github.com/thephpleague/fractaltransformer逻辑中的最佳方式。
我已经有了一个contactTransformer和companyTransformer,但是如果我将is_main添加到companyTransformer中,那么我所拨打的所有电话(与联系人相关或与联系人无关)也都将具有该属性。

最佳答案

如果我正确地阅读了,你可以使用一个单一的CompanyTransformer来处理你是否希望拥有is_main属性集,但是只有当一个$contact参数传递给它的构造函数时,沿着这条线:

class CompanyTransformer extends TransformerAbstract
{
    public function __construct(Contact $contact = null)
    {
        $this->contact = $contact;
    }

    public function transform(Company $company)
    {
        $output = [
            'id' => $company->id,
            'name' => $company->name,
        ];

        if($this->contact) {
            // This step may not be necessary, but I don't think the pivot data
            // will be available on the $company object passed in
            $company = $this->contacts->find($company->id);
            // You may have to cast this to boolean if that is important
            $output['is_main'] = $company->pivot->is_main;
        }

        return $output;
    }
}

然后在includeCompanyRelationship中输入新的CompanyTransformer参数:
public function includeCompanyRelationship(Contact $contact)
{
    $companies = $contact->companies;

    return $this->collection($companies, new CompanyTransformer($contact));
}

无论您是直接调用companies端点,还是在嵌入公司关系数据时调用联系人的端点,这都应该有效。

关于php - Laravel 5.1和Fractal:包括变压器上的数据透视表数据,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32697260/

10-09 16:52
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