这是将数据输入到mysql数据库中的php文件。当我运行它时,浏览器显示“已成功选择连接成功,正在执行的文件未插入内部”。但不会显示任何错误。并且数据不会插入数据库中。此代码有什么问题。
* dbConnection.php
<?php
$dbhost="localhost";
$dbuser="root";
$dbPassword="123";
$database="medicalcenter";
$connection = mysqli_connect($dbhost,$dbuser,$dbPassword) or die("unable to connect");
if($connection){
echo 'connected successfully ';
}else{
echo 'not connected';
}
$dbSelect=mysqli_select_db($connection,$database);
if($dbSelect){
echo 'selected successfully';
}else{
echo 'not selected';
}
?>
* insert.php
<?php
include 'dbConnection.php';
echo "Executing inside file";
$firstName = filter_input(INPUT_POST,'firstname');
$secondName = filter_input(INPUT_POST,'lastname');
$address1 =filter_input(INPUT_POST,'address1');
$address2 =filter_input(INPUT_POST,'address2');
$city =filter_input(INPUT_POST,'city');
$email =filter_input(INPUT_POST,'email');
$age =filter_input(INPUT_POST,'age');
$gender =filter_input(INPUT_POST,'gender');
$sql= "INSERT INTO patient(FirstName,LastName,AddressLine1,AddressLine2,City,Email,Age,Gender) VALUES ('$firstName','$secondName','$address1','$address2','$city',$email','$age','$gender')";
if(mysqli_query($connection,$sql)){
echo 'Inserted successfully';
}else{
echo 'Not Inserted';
}
mysqli_close($connection);
?>
最佳答案
$sql= "INSERT INTO patient(FirstName,LastName,AddressLine1,AddressLine2,City,Email,Age,Gender) VALUES ('$firstName','$secondName','$address1','$address2','$city',$email','$age','$gender')";
在发送电子邮件之前,请检查您忘记了
'
的上述行,请与以下行进行检查。希望对您有帮助。$sql= "INSERT INTO patient(FirstName,LastName,AddressLine1,AddressLine2,City,Email,Age,Gender) VALUES ('$firstName','$secondName','$address1','$address2','$city','$email','$age','$gender')";