ios - 如何根据从数据库中提取的数据在UITableView中出队正确的自定义单元格？

我有一个带有两个自定义UITableView类的UITableViewCell，我将它们定级并显示在表视图中。

我的情节提要看起来像这样：



以前，我是在数据中进行硬编码的，并且基于UITableView的indexPath.row，我将使适当的自定义单元格类出队并加载数据。

一个例子：

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
{
    switch (indexPath.row)
    {
        case 0...9:

            let 3Pic = tableView.dequeueReusableCell(withIdentifier: "3PicRow", for: indexPath) as! 3PicRowCell

            if indexPath.row == 0
            {
                3Pic.leftNameLabel.text = "Name"
                3Pic.leftPositionLabel.text = "Position"
                3Pic.leftImageView.image = UIImage(named: "icon")

                3Pic.MidddleNameLabel.text = "Name"
                3Pic.MiddlePositionLabel.text = "Position"
                3Pic.MiddleImageView.image = UIImage(named: "icon")

                3Pic.RightNameLabel.text = "Name"
                3Pic.RightPositionLabel.text = "Position"
                3Pic.RightImageView.image = UIImage(named: "icon")
            }
            else if indexPath.row == 1 // row=1 through row=9
            {
                // Do same thing
            }
            return 3Pic

        case 10...12:
            let 2Pic = tableView.dequeueReusableCell(withIdentifier: "2PicRow", for: indexPath) as! 2PicRowCell

            if indexPath.row == 10
            {
                2Pic.leftNameLabel.text = "Name"
                2Pic.leftPositionLabel.text = "Position"
                2Pic.leftImageView.image = UIImage(named: "icon_about")

                2Pic.rightNameLabel.text = "Name"
                2Pic.rightPositionLabel.text = "Position"
                2Pic.rightImageView.image = UIImage(named: "icon")
            }

            // Do same thing until row=12

            return 2Pic
        default:
            break;
    }

    // Will never reach here
    return UITableViewCell()
}

现在，我们正在迁移到严格从数据库中获取的数据，我现在很难根据自己获取的数据量来弄清楚如何使适当的单元出队。

JSON数据示例：

{
    "item1": {
        "id": 1,
        "first_name": "First",
        "last_name": "Last",
        "position": "Position",
        "image_url": "icon.com"
    },
    "item2": {
        "id": 2,
        "first_name": "First",
        "last_name": "Last",
        "position": "Position",
        "image_url": "icon.com"
    },
    "item3": {
        "id": 3,
        "first_name": "First",
        "last_name": "Last",
        "position": "Position",
        "image_url": "icon.com"
    }
}

谁能为我的困境提供解决方案？

最佳答案

您可以检查row JSON数据的键计数。如果您有3个键，请使用3pic单元格。如果您有2个按键，请使用2pic单元格。

伪代码如下所示：

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
{
    let jsonObject = jsonData[indexPath.row]
    let keyCount = jsonObject.keys.count

    if keyCount == 3 {
        3Pic.leftNameLabel.text = "Name"
        3Pic.leftPositionLabel.text = "Position"
        3Pic.leftImageView.image = UIImage(named: "icon")

        3Pic.MidddleNameLabel.text = "Name"
        3Pic.MiddlePositionLabel.text = "Position"
        3Pic.MiddleImageView.image = UIImage(named: "icon")

        3Pic.RightNameLabel.text = "Name"
        3Pic.RightPositionLabel.text = "Position"
        3Pic.RightImageView.image = UIImage(named: "icon")
    } else {
        2Pic.leftNameLabel.text = "Name"
        2Pic.leftPositionLabel.text = "Position"
        2Pic.leftImageView.image = UIImage(named: "icon_about")

        2Pic.rightNameLabel.text = "Name"
        2Pic.rightPositionLabel.text = "Position"
        2Pic.rightImageView.image = UIImage(named: "icon")
    }

    return cell
}

我确实认为使用集合视图将是一种更清洁的方法。您只需要1个单元格。