我的代码已经在数据库中插入数据,但是只有主键(AUTO_INCREMENT)是唯一添加的。我找不到日期和文字。

我的代码有问题吗?
这是我的代码如下:

HTML:

<form action="insertleave.php" method="post">
     <label>Date Filed:</label>
      <input type="date" name="datefiled">

      <label>Date of Leave:</label>
      <input type="date" name="leavedate">

  </div>
  <div class="medium-6 columns">
    <label>Reason of Leave:</label>
    <textarea rows="8" form="leaveform" name="reason"></textarea>
  </div>
  <input type="submit" class="expanded button" name="formSubmit" value="File Leave">
  </form>


PHP:

<?php
$datefiled = $_POST['datefiled'];
$leavedate = $_POST['leavedate'];
$leavereason = $_POST['leavereason'];

$config = parse_ini_file("phpconfig.ini");
$conn = mysqli_connect($config['host'], $config['username'], $config['password'], $config['dbname']);


if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}


   $sql = "INSERT INTO leaves (ID, EmployeeID,DateFiled, LeaveDate, Reason)
   VALUES
   ('$ID','$EmployeeID','$DateFiled','$LeaveDate','$Reason')";


  if (mysqli_query($conn, $sql)) {
    echo "OK!";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

mysqli_close($conn);
?>

最佳答案

在您的文本区域中,给它命名为“原因”

在您的post变量中,您的值为“ leavereason”

$leavereason = $_POST['leavereason'];更改为$leavereason = $_POST['reason'];

10-04 21:39
查看更多