以前，我使用php将表单数据附加到json文件中。目前我正在使用php文件而不是json文件，它有两个参数，如图所示，它显示给用户。
Image url link
我的表格是
<form action="process.php" method="POST">
Name:<br>
<input type="text" name="name">
<br><br/>
Download Url:<br>
<input type="text" name="downloadUrl">
<br><br>
<input type="submit" value="Submit">
</form>我的PHP文件是
{"downloadurl":[
{"name":"भाद्र ६ : LCR Series",
"downloadurl":"https://drive.google.com/uc?export=download&id=1In76AN2Y5_qXV5ucXDXWx1PTKTTIvD3d"
},
{"name":"भाद्र ६ : LCR Parallel",
"downloadurl":"https://drive.google.com/uc?export=download&id=1R9Ia4X12JZMsTn_vF6z443K6wKI2Rfeu"
}
]}我如何使用附加新数据，以便在单击“提交”按钮时将新数据添加到上述php文件的顶部，以便将新文件
{"downloadurl":[
{"name":"भाद्र ६ : New appended Data",
"downloadurl":"This is new Text added on Top"
},
{"name":"भाद्र ६ : LCR Series",
"downloadurl":"https://drive.google.com/uc?export=download&id=1In76AN2Y5_qXV5ucXDXWx1PTKTTIvD3d"
},
{"name":"भाद्र ६ : LCR Parallel",
"downloadurl":"https://drive.google.com/uc?export=download&id=1R9Ia4X12JZMsTn_vF6z443K6wKI2Rfeu"
}
]}在顶部，以便将其显示给用户
最佳答案
从您的问题来看，我认为这将解决您的问题。我正在使用array_unshift()，因为您对短语on top的使用使我认为您想在现有数据之前显示数据，如果这样做不正确，请用array_unshift()替换array_push()在数据之后添加，或参见解决方案2。
解决方案1：
<?php
//This is where your JSON file is located
$jsonFile = '/path/to/json/file';
//Get the contents of your JSON file, and make it a useable array.
$JSONString = json_decode( file_get_contents( $jsonFile ), true );
//This is the new data that you want to add to your JSON
$newData = array(
//Your data goes here
);
//Add the new data to the start of your JSON
array_unshift($existingData, $newData);
//Encode the new array back to JSON
$newData = json_encode( $existingData, JSON_PRETTY_PRINT );
//Put the JSON back into the file
file_put_contents($jsonFile, $newData);
?>
解决方案2：
<?php
//This is where your JSON file is located
$jsonFile = '/path/to/json/file';
//This is the new data that you want to add to your JSON
$newData = array(
//Your data goes here
);
//Encode the new data as JSON
$newData = json_encode( $newData, JSON_PRETTY_PRINT );
//append the new data to the existing data
file_put_contents( $jsonFile, $newData, FILE_APPEND );
?>