c++ - 读取二进制文件并解释数据

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我的目标是从二进制文件中读取数据，并最终将这些位存储在32bit slice中。我发现了几种不同的方法来读取C ++中的二进制文件，但是不确定哪种方法是最好的选择，我的主要问题是在存储数据后输出数据时，我没有访问单个位，而是显示ASCII字符。

int main(int argc, const char *argv[])
{

std::vector<char> memblock;
int i=0;
        ::std::ifstream in(argv[1], ::std::ios::binary);
        while (in) {
              char c;
              in.get(c);
              if (in) {
                 memblock.push_back(int(c));
                i++;
                  //::std::cout << "Read a " << int(c) << "\n";
              }
           }
std::cout << "The contents of memblock are:";
  for (std::vector<char>::iterator it = memblock.begin(); it != memblock.end(); ++it)
    std::cout << ' ' << *it;
  std::cout << '\n';
return 0;
}

并且：

streampos size;
      char * memblock;

      ifstream file ("path", ios::in|ios::binary|ios::ate);
      if (file.is_open())
      {
        size = file.tellg();
        memblock = new char [size];
        file.seekg (0, ios::beg);
        file.read (memblock, size);
        file.close();

        cout << "the entire file content is in memory";

       for(int i =0; i<10; i++){
           cout << memblock[i+2000];
       }
      }

每种方法都有优势吗？还是有更好的方法？另外，如何确保存储二进制文件中的实际位值或二进制数据？谢谢

最佳答案

您想读取32位整数，而不是char：

uint32_t * memblock;
ifstream file ("path", ios::in|ios::binary|ios::ate);
   if (file.is_open())
   {
       size = file.tellg();
       memblock = new unit32_t [size / 4 + (size % 4 == 0 ? 0 : 1)];
       file.seekg (0, ios::beg);
       file.read (reinterpret_cast<char*>(memblock), size);
       file.close();

       cout << "the entire file content is in memory";

       for(int i =0; i<size/4; i++){
            cout << memblock[i];
       }
    }