cocoa - (以递归方式)使用otool查找应用程序所需的共享库

我有一个使用otool的Cocoa应用程序，以查找应用程序正常运行所需的必需共享库。例如，假设我在使用QTKit.framework的应用程序上运行otool -L。我得到了程序使用的共享库的列表(包括诸如Cocoa.framework和AppKit.framework之类的基本框架):

/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/CoreFoundation.framework/Versions/A/CoreFoundation (compatibility version 150.0.0, current version 476.0.0)
    /System/Library/Frameworks/AppKit.framework/Versions/C/AppKit (compatibility version 45.0.0, current version 949.0.0)

..... and so on for a bunch of other frameworks

这表明该应用程序使用QTKit.framework。但是，如果我再次在QTKit.framework(/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit)的二进制文件上使用“otool -L”，则会得到以下信息:

/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/AudioToolbox.framework/Versions/A/AudioToolbox (compatibility version 1.0.0, current version 1.0.0)
/System/Library/PrivateFrameworks/CoreMedia.framework/Versions/A/CoreMedia (compatibility version 1.0.0, current version 1.0.0)
/System/Library/PrivateFrameworks/MediaToolbox.framework/Versions/A/MediaToolbox (compatibility version 1.0.0, current version 1.0.0)
/System/Library/PrivateFrameworks/VideoToolbox.framework/Versions/A/VideoToolbox (compatibility version 1.0.0, current version 1.0.0)
/System/Library/PrivateFrameworks/CoreMediaIOServices.framework/Versions/A/CoreMediaIOServices (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/Foundation.framework/Versions/C/Foundation (compatibility version 300.0.0, current version 751.0.0)
/System/Library/Frameworks/AppKit.framework/Versions/C/AppKit (compatibility version 45.0.0, current version 1038.0.0)
/System/Library/Frameworks/IOKit.framework/Versions/A/IOKit (compatibility version 1.0.0, current version 275.0.0)
/System/Library/Frameworks/QuickTime.framework/Versions/A/QuickTime (compatibility version 1.0.0, current version 1584.0.0)
/System/Library/Frameworks/CoreAudio.framework/Versions/A/CoreAudio (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/OpenGL.framework/Versions/A/OpenGL (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/QuartzCore.framework/Versions/A/QuartzCore (compatibility version 1.2.0, current version 1.6.0)
/System/Library/Frameworks/IOSurface.framework/Versions/A/IOSurface (compatibility version 1.0.0, current version 1.0.0)
/System/Library/Frameworks/Carbon.framework/Versions/A/Frameworks/HIToolbox.framework/Versions/A/HIToolbox (compatibility version 1.0.0, current version 435.0.0)
/usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0)
/usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 123.0.0)
/usr/lib/libobjc.A.dylib (compatibility version 1.0.0, current version 227.0.0)
/System/Library/Frameworks/CoreServices.framework/Versions/A/CoreServices (compatibility version 1.0.0, current version 44.0.0)
/System/Library/Frameworks/CoreFoundation.framework/Versions/A/CoreFoundation (compatibility version 150.0.0, current version 550.0.0)
/System/Library/Frameworks/ApplicationServices.framework/Versions/A/ApplicationServices (compatibility version 1.0.0, current version 38.0.0)
/System/Library/Frameworks/CoreVideo.framework/Versions/A/CoreVideo (compatibility version 1.2.0, current version 1.6.0)

这显示了应用程序二进制文件中原始otool输出显示的更多框架。 是否有一种方法可以让otool递归运行，这意味着它可以获取应用程序所需的框架，然后进入并在每个框架中搜索依赖关系？

最佳答案

不，您将不得不重复运行otool或合并其解析代码(here)。不要忘记处理@executable_path。

这里是Python(不支持@executable_path，规范化或带空格的文件名)，因为这比尝试调试伪代码要容易:

import subprocess

def otool(s):
    o = subprocess.Popen(['/usr/bin/otool', '-L', s], stdout=subprocess.PIPE)
    for l in o.stdout:
        if l[0] == '\t':
            yield l.split(' ', 1)[0][1:]

need = set(['/Applications/iTunes.app/Contents/MacOS/iTunes'])
done = set()

while need:
    needed = set(need)
    need = set()
    for f in needed:
        need.update(otool(f))
    done.update(needed)
    need.difference_update(done)

for f in sorted(done):
    print f