因此,我似乎无法正确满足此构造函数的要求。

DIVA_STATUS DIVA_getObjectDetailsList (
IN BOOL                   pFirstTime,
IN time_t                 *initialTime,
IN int                    pListType,
IN int                    pObjectsListType,
IN int                    pMaxListSize,
IN DIVA_STRING            pObjectName,
IN DIVA_STRING            pObjectCategory
IN DIVA_STRING            pMediaName
DIVA_LEVEL_OF_DETAIL      pLevelOfDetail,
IN vector<DIVA_STRING>    listPosition,
OUT vector<DIVA_OBJECT_DETAILS_LIST>      *&pObjectDetailsList
)

问题似乎是输出类 vector (???)的最后一行。我对C++有点生疏,所以我想不起来为什么要取消引用引用(*&)的原因。

DIVA_OBJECT_DETAILS_LIST是如下所示的类:
class DIVA_OBJECT_DETAILS_LIST {
public:
int                            listType;
DIVA_STRING                    siteID;
vector<DIVA_STRING>            *listPosition;
vector<DIVA_OBJECT_INFO>       *objectInfo;
vector<DIVA_OBJECT_TAPE_INFO>  *objectTapeInfo;
};

这是我尝试使用VC++ 2008 Express进行编译时得到的信息
1>Compiling...
1>initiator.cpp
1>.\initiator.cpp(148) : error C2100: illegal indirection
1>.\initiator.cpp(148) : error C2665: 'DIVA_getObjectDetailsList' : none of the 2 overloads could convert all the argument types
1>        z:\Mediavault1\Automation\DIVA_API\DIVArchiveAPI\CppAPI Test\include\DIVAapi.h(2191): could be 'DIVA_STATUS DIVA_getObjectDetailsList(bool,time_t,int,int,int,DIVA_STRING,DIVA_STRING,DIVA_STRING,DIVA_LEVEL_OF_DETAIL,std::vector<_Ty>,DIVA_OBJECT_DETAILS_LIST *&)'
1>        with
1>        [
1>            _Ty=DIVA_STRING
1>        ]
1>        while trying to match the argument list '(bool, time_t, int, int, int, DIVA_STRING, DIVA_STRING, DIVA_STRING, DIVA_LEVEL_OF_DETAIL, std::vector<_Ty>, DIVA_OBJECT_DETAILS_LIST *)'
1>        with
1>        [
1>            _Ty=DIVA_STRING
1>        ]

这是我调用构造函数的方式:
cr = DIVA_getObjectDetailsList (
                   _firstTime,
                   (time_t)_initDate,
                   (int)DIVA_OBJECTS_LIST,
                   (int)DIVA_OBJECTS_CREATED_SINCE,
                   _size,
                   _name,
                   _category,
                   _group,
                   DIVA_INSTANCE,
                   *_listType.listPosition,
                   &*_listType
                   );

_listType为DIVA_OBJECT_DETAILS_LIST。如何通过引用传递指针?

最佳答案

问题似乎出在倒数第二个参数上。当您只应传递std::vector<DIVA_STRING>*(而不是指针)时,您将传递std::vector<DIVA_STRING>

但是为了帮助您理解最后一个参数,vector<DIVA_OBJECT_DETAILS_LIST>*&是“对vector<DIVA_OBJECT_DETAILS_LIST>的指针的引用”类型。也就是说,您应该传递一个指针,并且该指针通过引用传递。

10-08 08:23
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