c++ - SWIG包装用于Python的C++ : translating a list of strings to an STL vector of STL strings

我想用SWIG包装一个C++函数，该函数接受STL字符串 vector 作为输入参数:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

void print_function(vector<string> strs) {
  for (unsigned int i=0; i < strs.size(); i++)
  cout << strs[i] << endl;
}

我想将其包装到名为mymod的模块中的Python函数中:

/*mymod.i*/
%module mymod
%include "typemaps.i"
%include "std_string.i"
%include "std_vector.i"

%{
 #include "mymod.hpp"
%}

%include "mymod.hpp"

当我用

from distutils.core import setup, Extension

setup(name='mymod',
  version='0.1.0',
  description='test module',
  author='Craig',
  author_email='balh.org',
  packages=['mymod'],
  ext_modules=[Extension('mymod._mymod',
                         ['mymod/mymod.i'],
                         language='c++',
                         swig_opts=['-c++']),
                         ],
  )

然后导入它并尝试运行它，我收到此错误:

Python 2.7.2 (default, Sep 19 2011, 11:18:13)
[GCC 4.1.2 20080704 (Red Hat 4.1.2-48)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import mymod
>>> mymod.print_function("hello is seymour butts available".split())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: in method 'print_function', argument 1 of type 'std::vector<  std::string,std::allocator< std::string > >'
>>>

我猜这是在说SWIG没有提供用于在Python字符串列表和STL字符串的C++ STL vector 之间进行转换的默认类型映射。我觉得这是他们默认情况下可能会提供的东西，但是也许我不知道要包含的文件正确。那么我怎样才能使它正常工作呢？

提前致谢!

最佳答案

您需要告诉SWIG您想要 vector 字符串类型映射。它不能神奇地猜测所有可能存在的所有不同 vector 类型。

这是Schollii提供的链接:

//To wrap with SWIG, you might write the following:

%module example
%{
#include "example.h"
%}

%include "std_vector.i"
%include "std_string.i"

// Instantiate templates used by example
namespace std {
   %template(IntVector) vector<int>;
   %template(DoubleVector) vector<double>;
   %template(StringVector) vector<string>;
   %template(ConstCharVector) vector<const char*>;
}

// Include the header file with above prototypes
%include "example.h"