我已经成功地在列表 View 中显示了API响应,但是我想在按下列表 View 时可以获取列表 View 项的ID。我如何获得ID?
我有如下的API响应:
"payload": [
{
"id": "402",
"desc": "FAR"
},
{
"id": "406",
"desc": "HGR"
},
{
"id": "403",
"desc": "Baf"
},
]
这是我制造的集团:
我很困惑如何单击列表 View 项时获取ID,这是怎么回事?
class ListMultibillBloc {
final _repository = EresidenceRepository();
SharedPreferences sPrefs;
final BehaviorSubject<List<Payload>> _subject = BehaviorSubject<List<Payload>>();
listMultibill() async{
try{
sPrefs = await SharedPreferences.getInstance();
ListServiceMultibill responses = await _repository.listServiceMultibill(sPrefs.getString("userid"), sPrefs.getString("password"), sPrefs.getString("imei"),
sPrefs.getString("coordinate"), sPrefs.getString("bnr"));
List<Payload> list = responses.data.payload;
_subject.sink.add(list);
}catch(e){
print(e.toString());
_subject.sink.add(e);
}
}
dispose(){
_subject.close();
}
BehaviorSubject<List<Payload>> get subject => _subject;
}
final listMultibill = ListMultibillBloc();
这是UI部分:
我可以显示数据列表
class _ListMultibillState extends State<ListMultibill> {
@override
void initState() {
listMultibill.listMultibill();
super.initState();
}
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
body: StreamBuilder(
stream: listMultibill.subject,
builder: (context, AsyncSnapshot<List<Payload>> snapshot) {
if (snapshot.hasData) {
print(snapshot.data);
return buildList(snapshot);
}else{
Error();
}
},
),
),
);
}
Widget buildList(AsyncSnapshot<List<Payload>> snapshot) {
return ListView.builder(
itemCount: snapshot.data.length,
itemBuilder: (BuildContext context, int index) {
return ListTile(
title: Text(
snapshot.data[index].desc,
style: AppTheme.styleSubTitleBlackSmall,
),
);
}
);
}
}
最佳答案
您可以在ListTile中添加onTap
,
onTap:() {
print("${snapshot.data[index].id}");
},