为此一直奋斗了一段时间。我的方法如下所示:
public Frame(){
JFrame window = new JFrame();
window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
window.setSize(800, 600);
JPanel panel = new JPanel(new GridBagLayout());
GridBagConstraints gbc = new GridBagConstraints();
gbc.gridheight =3;
gbc.gridwidth = 3;
JButton upButt = new JButton();//Buttons.upButton();
gbc.gridx = 1;
gbc.gridy = 0;
panel.add(upButt, gbc);
JButton downButt = new JButton();
gbc.gridx = 1;
gbc.gridy = 2;
panel.add(downButt, gbc);
JButton leftButt = new JButton();//Buttons.leftButton();
gbc.gridx=0;
gbc.gridy = 1;
panel.add(leftButt, gbc);
JButton rightButt = new JButton();//Buttons.rightButton();
gbc.gridx =2;
gbc.gridy = 1;
panel.add(rightButt, gbc);
window.add(panel);
window.setVisible(true);
}
根据我的理解-阅读并重新阅读Java文档之后。 -这应该给我4个十字形的按钮。但是情况并非如此,按钮在窗口中心彼此堆叠。
我想念什么?
最佳答案
为什么使用gridheight和gridwidth为3?至少可以说这有点奇怪。
为了我的钱,我将简化事情并使用一个简单的GridLayout:
import java.awt.GridLayout;
import javax.swing.*;
public class Foo003 {
public static void main(String[] args) {
JButton upButton = new JButton("Up");
JButton downButton = new JButton("Down");
JButton leftButton = new JButton("Left");
JButton rightButton = new JButton("Right");
JComponent[][] components = {
{ new JLabel(), upButton, new JLabel() },
{ leftButton, new JLabel(), rightButton },
{ new JLabel(), downButton, new JLabel() } };
JPanel panel = new JPanel(new GridLayout(components.length,
components[0].length, 8, 8));
for (int i = 0; i < components.length; i++) {
for (int j = 0; j < components[i].length; j++) {
panel.add(components[i][j]);
}
}
int eb = 15;
panel.setBorder(BorderFactory.createEmptyBorder(eb, eb, eb, eb));
JFrame frame = new JFrame("Grid e.g.");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.getContentPane().add(panel);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
}