java - Java Spring中POST请求@ManyToOne关系的JSON内容

我有两个模型:
第一类:

import javax.persistence.*;
import java.util.Set;

@Entity
public class One {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    private String name;
    @OneToMany(mappedBy = "one")
    private Set<Many> manySet;

    //Constructor, Getter and Setter
}

许多类:

import javax.persistence.*;

@Entity
public class Many {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    private String name;
    @ManyToOne
    @JoinColumn(name = "one_id")
    private One one;
    //Constructor, Getter and Setter
}

仓库:

import com.hotel.model.Many;
import org.springframework.data.jpa.repository.JpaRepository;

public interface ManyRepository extends JpaRepository<Many, Long> {
}

控制器类别:

@RestController
@RequestMapping(value = "many")
public class ManyController {
    @Autowired
    private ManyRepository manyRepository;

    @GetMapping
    @ResponseBody
    public List<Many> getAllMany() {
        return manyRepository.findAll();
    }

    @PostMapping
    @ResponseBody
    public ResponseEntity createMany(@RequestBody Many many) {
        return new ResponseEntity(manyRepository.save(many), HttpStatus.CREATED);
    }
}

我创建了一个ID为1的记录。
但是，当我使用JSON数据创建Many记录时:

{
    "name": "Foo",
    "one_id": 1
}

我收到了许多带有one_id的记录是null我可以仅使用一个请求来创建新的“多条记录”并分配给ID为1的“一条记录”吗？
我是否必须使用2个请求:创建多个并分配给一个？

最佳答案

您必须像这样更新您的方法

@PostMapping
@ResponseBody
public ResponseEntity createMany(@RequestBody ManyDTO many) {
    One one = oneRepository(many.getOne_id()); //Get the parent Object
    Many newMany  = new Many(); //Create a new Many object
    newMany.setName(many.getName());
    newMany.setOne(one); // Set the parent relationship

    ...

}

注意:上面的答案仅说明了设置实体关系的方法。正确的服务层应该被实际调用。