我在使函数使用jQuery动画设置某些div的位置时遇到一些问题。我使用jQuery进行了测验,并希望带有数字ID的正确的“已回答”可拖动div自动转到具有相同ID的目标位置div。这是用于导航(每次仅显示12个问题)。
HTML看起来像这样
<div id="container"> //floats left
<div class="answer" id="1"></div> //droppables
<div class="answer" id="2"></div>
<div class="answer" id="3"></div>
<div class="answer" id="4"></div>
<div class="answer" id="5"></div>
<div class="answer" id="6"></div>
<div class="answer" id="7"></div>
<div class="answer" id="8"></div>
<div class="answer" id="9"></div>
<div class="answer" id="10"></div>
<div class="answer" id="11"></div>
<div class="answer" id="12"></div>
</div>
<div id="container>
<div class="drag" id="3"></div> //draggables are in random order
<div class="drag" id="1"></div>
<div class="drag" id="2"></div>
<div class="drag" id="6"></div>
<div class="drag" id="5"></div>
<div class="drag" id="12"></div>
<div class="drag" id="4"></div>
<div class="drag" id="8"></div>
<div class="drag" id="7"></div>
<div class="drag" id="11"></div>
<div class="drag" id="9"></div>
<div class="drag" id="10"></div>
</div>
每当有人将正确的可拖动对象放到正确的可放置对象上时,id就会存储在名为
rightIds
的数组中。可以说rightIds是
array(0=>3, 1=>7 2=>9)
我还有一个名为
currentIds
的数组,其中包含现在显示的ID。currentIds
现在是array(0=>1 to 11=>12)
我做了这个功能:
function resetAnimation(currentIds, rightIds) {
$.each(currentIds, function (index, value) {
$.each(rightIds, function(ind, val) {
console.log('currentIds value: ' + value);
console.log('rightIds val: ' + val);
if (val == value) {
var target = $('#' + value + '.answer');
console.log(target);
var targetTop = target.offset().top;
console.log('targetTop: ' + targetTop);
var targetLeft = target.offset().left;
console.log('targetLeft: ' + targetLeft);
var drag = $('#' + value + '.drag');
console.log(drag);
var dragTop = drag.offset().top;
console.log('dragTop: ' + dragTop);
var dragLeft = drag.offset().left;
console.log('dragLeft: ' + dragLeft);
drag.animate({
'top': -target.offset().top,
'left': -target.offset().left
}, 3000);
}
});
});
}
但是当我运行它时,拖动div不会到达目标位置,而是会到达其他位置。当我检查动画元素时,偏移量与目标偏移量相同,仅在值前加上“-”。我希望有人能告诉我我在做什么错以及如何解决这个问题。
谢谢
最佳答案
在您的代码中,如果您的drag元素位于相同的offset父级中,并且两个元素都位于绝对位置,则它应该与替换一样简单:
drag.animate({
'top': -target.offset().top,
'left': -target.offset().left
}, 3000);
带有:
drag.animate({
'top': target.offset().top,
'left': target.offset().left
}, 3000);
如果不是绝对定位,则它与设置偏移量并不完全相同,jQuery非常聪明,可以得出正确的相对定位,但是动画不使用此相同功能。如果失败,您可以使用:
$drag.animate(
{ top: $target.position().top - $drag.position().top
, left: $target.position().left - $drag.position().left }, 3000);
用法示例
版本1-jQuery匹配
HTML已更新,因此按nnnnnn的正确建议有效(没有重复的ID):
<div class="container">
<div class="answer" id="answer-1"></div>
<div class="answer" id="answer-2"></div>
<div class="answer" id="answer-3"></div>
<div class="answer" id="answer-4"></div>
<div class="answer" id="answer-5"></div>
<div class="answer" id="answer-6"></div>
<div class="answer" id="answer-7"></div>
<div class="answer" id="answer-8"></div>
<div class="answer" id="answer-9"></div>
<div class="answer" id="answer-10"></div>
<div class="answer" id="answer-11"></div>
<div class="answer" id="answer-12"></div>
</div>
<div class="container">
<div class="drag" id="drag-3"></div>
<div class="drag" id="drag-1"></div>
<div class="drag" id="drag-2"></div>
<div class="drag" id="drag-6"></div>
<div class="drag" id="drag-5"></div>
<div class="drag" id="drag-12"></div>
<div class="drag" id="drag-4"></div>
<div class="drag" id="drag-8"></div>
<div class="drag" id="drag-7"></div>
<div class="drag" id="drag-11"></div>
<div class="drag" id="drag-9"></div>
<div class="drag" id="drag-10"></div>
</div>
<div>
<a id="get-answers">Get answers</a>
</div>
这样,JavaScript可以简化为将drag- [id]与answer- [id]匹配,并使用position jQuery method将drag元素移动到正确的位置:
// Animates right answered draggables
// to the right answers
function resetAnimation() {
// Iterate over all of the drag elements
$(".drag").each(function() {
var $drag = $(this)
// Get the id of the drag element
// by dropping "drag-" off the front
, id = $drag.attr("id").replace("drag-", "")
// Find the matching answer
, $target = $('#answer-' + id);
// The animation code, position gives
// the coordinates of the element relative
// to the offset parent, subtract the original
// position from the target position to get the
// correct translation deltas
$drag.animate(
{ top: $target.position().top - $drag.position().top
, left: $target.position().left - $drag.position().left}, 3000);
});
}
$(function() {
$("#get-answers").click(resetAnimation);
});
版本2-数组匹配
如果您确实想坚持使用数组来实现此目的(我将使用对象文字并将其个人视为字符串ID),则对代码的修改如下:
// Animates right answered draggables
// to the right answers
function resetAnimation(answered, correct) {
// Iterate over all of the drag elements
for(var id in answered) {
if(answered[id] !== correct[id]) {
var $drag = $("#drag-" + id)
// Find the matching answer
, $target = $('#answer-' + correct[id]);
// The animation code, position gives
// the coordinates of the element relative
// to the offset parent, subtract the original
// position from the target position to get the
// correct translation deltas
$drag.animate(
{ top: $target.position().top - $drag.position().top
, left: $target.position().left - $drag.position().left}, 3000);
}
}
}
$(function() {
$("#get-answers").click(function() {
resetAnimation({
"1" : "3",
"2" : "2",
"3" : "1"
}, {
"1" : "2",
"2" : "3",
"3" : "1"
});
});
});
我用于这些测试用例的CSS:
.answer {
float: left;
margin: 10px;
background: red;
width: 20px;
height: 20px;
}
.drag {
position: relative;
float: left;
margin: 10px;
background: green;
width: 20px;
height: 20px;
}
.container {
float: left;
width: 100%;
}
Here's a fiddle