IOS的Emoji表情因为编码问题,在Android手机上无法正常显示,如果当前的cc.Label节点使用的是系统字,在系统字库中找不到对应编码的字符,会导致崩溃。
为了解决这个问题,又要兼顾新老版本,要在3个地方做调整:
- Android虚拟键盘输入时,屏蔽Emoji;
- IOS虚拟键盘输入时,屏蔽Emoji;
- Lua端屏蔽Emoji;
一、Android端屏蔽Emoji
1、在Cocos2dxHelper.java类中添加过滤Emoji方法
private static boolean containsEmoji(String source) {
if (null == source || 0 == source.length()) {
return false;
}
int len = source.length();
for (int i = 0; i < len; i++) {
char c = source.charAt(i);
if (isEmojiCharacter(c)) {
return true;
}
}
return false;
}
private static boolean isEmojiCharacter(char c) {
return !((c == 0x0) || (c == 0x9) || (c == 0xA)
|| (c == 0xD)
|| ((c >= 0x20) && (c <= 0xD7FF))
|| ((c >= 0xE000) && (c <= 0xFFFD))
|| ((c >= 0x10000) && (c <= 0x10FFFF)));
}
private static String filterEmoji(String source) {
if (!containsEmoji(source)) {
return source;// don't contain, just return
}
StringBuilder buf = null;
int len = source.length();
for (int i = 0; i < len; i++) {
char c = source.charAt(i);
if (!isEmojiCharacter(c)) {
if (buf == null) {
buf = new StringBuilder(source.length());
}
buf.append(c);
}
}
if (buf == null) {
return null;
} else {
if (buf.length() == len) {
buf = null;
return source;
} else {
return buf.toString();
}
}
}
2、修改Cocos2dxHelper.java类的setEditTextDialogResult方法
把代码
final byte[] bytesUTF8 = pResult.getBytes("UTF8");
修改为
String text = filterEmoji(pResult);
if (null == text || 0 == text.length()) {
text = "";
}
final byte[] bytesUTF8 = text.getBytes("UTF8");
二、IOS屏蔽Emoji表情
IOS的Emoji表情的输入有两种方式:一种是Emoji表情页,另一种是输入法打字联想出来的。
1、屏蔽Emoji表情页中的表情输入
- (BOOL)textField:(UITextField *) textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
if ([textField isFirstResponder]) {
if([[[textField textInputMode] primaryLanguage] isEqualToString:@"emoji"] || ![[textField textInputMode] primaryLanguage]) {
return NO;
}
}
...
...
}
2、过滤输入法联想出来的Emoji:
1)检测并过滤Emoji表情
// 过滤所有表情。containEmoji为NO表示不含有表情,YES表示含有表情
- (BOOL)stringContainsEmoji:(UITextField *)textField
{
__block BOOL containEmoji = NO;
self.stringAfterFilterEmoji = @"";
NSString* string = textField.text;
[string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
const unichar hs = [substring characterAtIndex:0];
BOOL is_emoji = NO;
// surrogate pair
if (0xd800 <= hs && hs <= 0xdbff) {
if (substring.length > 1) {
const unichar ls = [substring characterAtIndex:1];
const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
if (0x1d000 <= uc && uc <= 0x1f77f) {
is_emoji = YES;
}
}
} else if (substring.length > 1) {
const unichar ls = [substring characterAtIndex:1];
if (ls == 0x20e3) {
is_emoji = YES;
}
} else {
// non surrogate
if (0x2100 <= hs && hs <= 0x27ff) {
is_emoji = YES;
} else if (0x2B05 <= hs && hs <= 0x2b07) {
is_emoji = YES;
} else if (0x2934 <= hs && hs <= 0x2935) {
is_emoji = YES;
} else if (0x3297 <= hs && hs <= 0x3299) {
is_emoji = YES;
} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {
is_emoji = YES;
}
}
if (!is_emoji) {
self.stringAfterFilterEmoji = [self.stringAfterFilterEmoji stringByAppendingString:substring];
}
containEmoji = is_emoji ? is_emoji : containEmoji;
}];
return containEmoji;
}
2)应用过滤过的输入
- (BOOL)textFieldShouldEndEditing:(UITextField *)sender {
if ([self stringContainsEmoji:sender]) {
sender.text = self.stringAfterFilterEmoji;
}
...
...
}
三、Lua屏蔽Emoji
由于要兼顾老版本,不仅仅要在输入端对Emoji进行过滤,如果老版本使用Emoji,同样要添加过滤;但Lua的编码跟Java和OC有很大不同,Java可以通过char、OC通过unichar可以获取Unicode字符,但Lua不行,Lua是通过string的字节链接的形式来存储Unicode的字符;
通过总结发现,一个Emoji表情的第1个字节(string.byte(s, 1))等于240,第2个字节(string.byte(s,2))等于159的不能被Android识别,从而崩溃,因此可以过滤此种Emoji,从而解决崩溃问题。
function M:getByteCount( byte )
local ret = 0
if byte > 0 and byte <= 127 then
ret = 1
elseif byte >= 192 and byte < 223 then
ret = 2
elseif byte >= 224 and byte < 239 then
ret = 3
elseif byte >= 240 and byte <= 247 then
ret = 4
end
return ret
end
function M:filterEmoji( source )
local len = string.len(source)
if len < 2 then return source end
local ret_str = ""
local i = 1
while i <= len do
local is_emoji = false
local byte_1 = string.byte(source, i)
if byte_1 == 240 then
local byte_2 = string.byte(source, i + 1)
if byte_2 == 159 then
is_emoji = true
end
end
local byte_count = self:getByteCount(byte_1)
byte_count = byte_count < 1 and 1 or byte_count
if not is_emoji then
ret_str = ret_str..string.sub(source, i, i + byte_count - 1)
end
i = i + byte_count
end
return ret_str
end