传送门

解题思路

  一道%你神题,\(string\)好强大啊。。首先枚举一个周几,再枚举一个罪犯是谁,然后判断的时候就是枚举所有人说的话。定义\(fAKe[i]\)表示第\(i\)个人说的是真话还是假话还是未知。然后如果遇到\(xx is guilty\)或\(I am guilty\)之类的话,就看枚举的罪犯是否为这个人。如果说的是\(Today is xxx\),就看当前枚举的星期是否为这一天。

代码

#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<string>
#include<map> using namespace std;
const int MAXN = 25; int n,m,p,fAKe[MAXN],w[205],ans,now,err;
string name[MAXN],say[205];
string day[10]={"","Today is Sunday.","Today is Monday.","Today is Tuesday.","Today is Wednesday."
,"Today is Thursday.","Today is Friday.","Today is Saturday."};
map<string,int> mp; void solve(int x,int y){
if(!fAKe[x]) fAKe[x]=y;
else if(fAKe[x] && fAKe[x]!=y) err=1;
} int main(){
scanf("%d%d%d",&m,&n,&p);
for(int i=1;i<=m;i++) cin>>name[i],mp[name[i]]=i;
for(int i=1;i<=p;i++){
string nm;cin>>nm;
nm.erase(nm.end()-1);w[i]=mp[nm];
getline(cin,say[i]);say[i].erase(say[i].begin());
say[i].erase(say[i].end()-1);
}
for(int td=1;td<=7;td++)
for(int chp=1;chp<=m;chp++){ //枚举罪犯
err=0;int who,cnt,pp;
memset(fAKe,0,sizeof(fAKe));
for(int i=1;i<=p;i++){
who=w[i];
if(say[i]=="I am guilty.") solve(who,who==chp?1:-1);
if(say[i]=="I am not guilty.") solve(who,who==chp?-1:1);
for(int j=1;j<=7;j++)
if(say[i]==day[j]) {solve(who,j==td?1:-1);break;}
for(int j=1;j<=m;j++){
if(say[i]==name[j]+" is guilty.") solve(who,chp==j?1:-1);
if(say[i]==name[j]+" is not guilty.") solve(who,chp==j?-1:1);
}
}
cnt=pp=0;
for(int i=1;i<=m;i++) {
if(!fAKe[i]) pp++;
if(fAKe[i]==-1) cnt++;
}
if(err || cnt>n || cnt+pp<n) continue;
if(ans && ans!=chp) {
puts("Cannot Determine");
return 0;
}
ans=chp;
}
if(ans) cout<<name[ans];
else puts("Impossible");
return 0;
}
05-17 03:33