目标:

  1.实现两个数的加减法

  2.回答者3次输错计算结果后,输出正确结果,并询问回答者是否继续

1.使用常规函数实现两个数的加减法游戏

代码如下:

#!/usr/bin/env python
# -*- coding: utf-8 -*- '''使用常规函数编写出题游戏''' import random def add(x,y):
return x + y def sub(x,y):
return x - y def chuti():
cmds = {'+': add, '-': sub}
ops = '+-'
op = random.choice(ops)
nums = [random.randint(1,50) for i in xrange(2)]
nums.sort(reverse=True)
prompt = '%s %s %s = ' %(nums[0], op, nums[1])
anwser = cmds[op](*nums) counter = 0
while counter < 3:
try:
result = int(raw_input(prompt))
except:
continue
if anwser == result:
print "回答正确"
print "-" * 20
break
else:
counter += 1
print "回答错误"
print "-" * 20
else:
print "正确答案是: %s %s" % (prompt, anwser) if __name__ == "__main__":
while True:
chuti()
try:
yn = raw_input("Continue(y/n?)").strip()[0]
except IndexError:
continue
except (KeyboardInterrupt,EOFError):
yn = 'n'
if yn in 'Nn':
print "结束"
break

•运行代码,测试效果

[root@localhost python]# python new_mathgame.py
27 + 25 = 5
回答错误
--------------------
27 + 25 = 2
回答错误
--------------------
27 + 25 = 3
回答错误
--------------------
正确答案是: 27 + 25 = 52
Continue(y/n?)y
15 - 1 = 12
回答错误
--------------------
15 - 1 = 13
回答错误
--------------------
15 - 1 = 14
回答正确
--------------------
Continue(y/n?)n
结束

2.使用lambda匿名函数实现两位数的加减法游戏

代码如下:

#!/usr/bin/env python
# -*- coding: utf-8 -*- '''使用匿名函数lambda编写出题游戏''' import random
# def add(x,y):
# return x + y # def sub(x,y):
# return x - y
def chuti():
cmds = {'+': lambda x, y: x + y, '-': lambda x, y: x - y}
ops = '+-'
op = random.choice(ops)
nums = [random.randint(1,50) for i in xrange(2)]
nums.sort(reverse=True)
prompt = '%s %s %s = ' %(nums[0], op, nums[1])
anwser = cmds[op](*nums) counter = 0
while counter < 3:
try:
result = int(raw_input(prompt))
except:
continue
if anwser == result:
print "回答正确"
print "-" * 20
break
else:
counter += 1
print "回答错误"
print "-" * 20
else:
print "正确答案是: %s %s" % (prompt, anwser) if __name__ == "__main__":
while True:
chuti()
try:
yn = raw_input("Continue(y/n?)").strip()[0]
except IndexError:
continue
except (KeyboardInterrupt,EOFError):
yn = 'n'
if yn in 'Nn':
print "结束"
break
05-11 22:26