Source:

Description:

Input Specification:

Output Specification:

Sample Input:

Sample Output:

Keys:

Attention:

  • 给出的N个皇后可能在同一行

Code:

 /*
Data: 2019-05-25 10:24:05
Problem: PAT_A1128#N Queens Puzzle
AC: 18:04 题目大意:
判断给定的序列是否为N皇后问题的解
输入:
第一行给出:测试数K<=200;
接下来K行,问题规模N<=1e3,N个数
输出:
Yes or No
*/ #include<cstdio>
#include<algorithm>
using namespace std;
const int M=1e3+; int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("Test.txt", "r", stdin);
#endif int n,m;
scanf("%d", &m);
while(m--)
{
scanf("%d", &n);
int q[M],ans=;
for(int i=; i<=n; i++)
scanf("%d", &q[i]);
for(int i=; i<=n; i++)
{
for(int j=i+; j<=n; j++)
if(abs(j-i)==abs(q[j]-q[i]) || q[j]==q[i]){
ans=;break;
}
if(ans==)
break;
}
if(ans) printf("YES\n");
else printf("NO\n");
} return ;
}
05-11 20:25