LeetCode——Hamming Distance
Question
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 2^31.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
The above arrows point to positions where the corresponding bits are different.
具体实现
class Solution {
public:
int hammingDistance(int x, int y) {
int tmp = x ^ y;
int res = 0;
while (tmp > 0) {
if (tmp % 2 != 0)
res++;
tmp = tmp >> 1;
}
return res;
}
};