C堆栈实现的表达式求值

//Luangeng
#include<stdio.h>
#include<conio.h>
#include<windows.h>
#define SIZE 100
char t[10][14]={0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,1,1,0,1,1,1,0,1,1,1,1,1,0,
0,1,1,1,1,0,1,1,1,0,1,0,1,0,
0,0,0,1,0,0,1,0,1,0,0,1,1,0,
0,1,1,1,1,1,0,1,0,1,1,0,1,0,
0,1,0,1,0,1,0,1,1,1,0,1,0,0,
0,1,1,0,1,0,1,0,0,1,1,0,1,0,
0,1,0,1,1,1,0,1,1,1,1,1,0,0,
0,1,1,1,0,1,1,1,0,1,0,1,1,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0};
typedef struct { short x,y; short d; } step;
typedef struct { step *top,*base; } stack;
void gotoxy(int x,int y)
{
COORD cd;
cd.X = x;
cd.Y = y;
HANDLE hout=GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorPosition(hout,cd);
}
void creat(stack *s)
{ s->base=(step *)malloc(SIZE*sizeof(step));
s->top=s->base;
if(!s->base) printf("failed !\n");
}
void push(stack *s,short a,short b,short c)
{ if(s->top>=(s->base+SIZE))
printf("stack full !..........");
else
{ s->top++;
s->top->x=a;
s->top->y=b;
s->top->d=c;
gotoxy(b,a);
printf("%c",1);
}
}
void pop(stack *s)
{ if(s->base==s->top) printf("\nunderflow....\n");
else { gotoxy(s->top->y,s->top->x); printf(" "); s->top--; }
}
int main()
{ stack path;
short i,j,k;
creat(&path);
for(i=1;i<=10;i++)
for(j=1;j<=14;j++)
{
gotoxy(j,i);
if(t[i-1][j-1]==0)
printf("%s","#");
else printf(" ");
}
k=1;
push(&path,2,2,4); t[1][1]=-1;
while(!(path.top->x==9&&path.top->y==13))
{ switch(path.top->d)
{
case 4:
path.top->d--;
if(t[path.top->x-2][path.top->y-1]==1)
{
t[path.top->x-2][path.top->y-1]=-1;
push(&path,path.top->x-1,path.top->y,4); k++;
}
break;
case 3:
path.top->d--;
if(t[path.top->x-1][path.top->y]==1)
{ t[path.top->x-1][path.top->y]=-1;
push(&path,path.top->x,path.top->y+1,4); k++;
}
break;
case 2:
path.top->d--;
if(t[path.top->x][path.top->y-1]==1)
{ t[path.top->x][path.top->y-1]=-1;
push(&path,path.top->x+1,path.top->y,4); k++;
}
break;
case 1:
path.top->d--;
if(t[path.top->x-1][path.top->y-2]==1)
{ t[path.top->x-1][path.top->y-2]=-1;
push(&path,path.top->x,path.top->y-1,4); k++;
}
break;
case 0: pop(&path); k--; break;
}
if(path.top==path.base)
{ gotoxy(17,1);
printf("No way out !!");
break;
}
sleep(5);
gotoxy(17,10); printf("step=%d; ",k);
}
system("pause");
}

  

05-11 15:48