package main

import (
"fmt"
"sync"
) var l sync.Mutex
var a string func f() {
a = "hello, world"
l.Unlock()
} //还是需要加锁的!!!
type testClass struct {
mutex sync.Mutex
x []byte
} func (this *testClass) init() {
this.x = make([]byte, 0)
} func (this *testClass) addx(val byte) {
this.mutex.Lock()
defer this.mutex.Unlock()
this.x = append(this.x, val)
} func (this *testClass) print() {
fmt.Println(this.x)
} var x1 chan int var x2 chan int func f1(txtcls *testClass) {
txtcls.addx('x')
x1 <- 1
} func f2(txtcls *testClass) {
txtcls.addx('y')
x2 <- 1
} func main() {
x1 = make(chan int)
x2 = make(chan int)
var txtcls testClass
txtcls.init() go f1(&txtcls) go f2(&txtcls) select {
case <-x1:
fmt.Println("xxxxx")
} select {
case <-x2:
fmt.Println("yyyyy")
} txtcls.print() /*
l.Lock()
go f()
l.Lock()
print(a)
l.Unlock()
*/
}

  以上代码说明如下问题,2个协程同时对一个对象指针变量进行读操作的时候需要进行加锁

那么不加有什么问题呢:

会出现打印出只有一个变量的情况

05-11 14:01