Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
if(nums1.empty()||nums2.empty())
return;
int idx1=m-;
int idx2=n-;
int len=m+n-;
while(idx1>=&&idx2>=)
{
if(nums1[idx1]>=nums2[idx2])
nums1[len--]=nums1[idx1--];
else
nums1[len--]=nums2[idx2--];
}
while(idx2>=)
nums1[len--]=nums2[idx2--];
}
};