容易发现只要图中有非链部分则无解。剩下就非常简单了。
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std;
int read()
{
int x=,f=;char c=getchar();
while (c<''||c>'') {if (c=='-') f=-;c=getchar();}
while (c>=''&&c<='') x=(x<<)+(x<<)+(c^),c=getchar();
return x*f;
}
#define N 500010
#define P 989381
int n,m,fa[N],degree[N],size[N];
struct data
{
int x,y;
bool operator <(const data&a) const
{
return x<a.x||x==a.x&&y<a.y;
}
bool operator ==(const data&a) const
{
return x==a.x&&y==a.y;
}
}a[N];
int find(int x){return fa[x]==x?x:fa[x]=find(fa[x]);}
int main()
{
#ifndef ONLINE_JUDGE
freopen("bzoj3444.in","r",stdin);
freopen("bzoj3444.out","w",stdout);
const char LL[]="%I64d\n";
#else
const char LL[]="%lld\n";
#endif
n=read(),m=read();
for (int i=;i<=m;i++)
{
a[i].x=read(),a[i].y=read();
if (a[i].x>a[i].y) swap(a[i].x,a[i].y);
}
sort(a+,a+m+);
int t=unique(a+,a+m+)-a-;
for (int i=;i<=n;i++) fa[i]=i;
for (int i=;i<=t;i++)
if (find(a[i].x)==find(a[i].y)) {cout<<;return ;}
else fa[find(a[i].x)]=find(a[i].y),degree[a[i].x]++,degree[a[i].y]++;
int cnt=;
for (int i=;i<=n;i++)
if (degree[i]>) {cout<<;return ;}
else if (find(i)==i) cnt++;
else size[find(i)]++;
t=;
for (int i=;i<=n;i++)
if (find(i)==i&&size[i]) t++;
int ans=;
for (int i=;i<=t;i++) ans=(ans<<)%P;
for (int i=;i<=cnt;i++) ans=1ll*ans*i%P;
cout<<ans;
return ;
}