高效 python (2)

一个班的学生姓名和成绩如下，打印出及格学生的姓名及成绩：

A	B	C	D	E	F	G
67	41	88	99	65	55	27

C:

1. #include <stdio.h>
   
2. 
   
3. typedef struct {
   
4.         char name[255];
   
5.         int score;
   
6. } testInfoT;
   
7. 
   
8. int main()
   
9. {
   
10.         testInfoT ti[] = {
    
11.                 {"A", 67},
    
12.                 {"B", 41},
    
13.                 {"C", 88},
    
14.                 {"D", 99},
    
15.                 {"E", 65},
    
16.                 {"F", 55},
    
17.                 {"G", 27},
    
18.         };
    
19. 
    
20.         for (int i = 0; i < sizeof(ti) / sizeof(testInfoT); i++){
    
21.                 if (ti[i].score > 60){
    
22.                         printf("%s:%d\n", ti[i].name, ti[i].score);
    
23.                 }
    
24.         }
    
25. 
    
26.         return 0;
    
27. }

python:

1. testInfo = {
   
2.         "A":67, \
   
3.         "B":41, \
   
4.         "C":88, \
   
5.         "D":99, \
   
6.         "E":65, \
   
7.         "F":55, \
   
8.         "G":27}
   
9. 
   
10. print(filter(lambda x : x[1] > 60, testInfo.items()))

filter(function, sequence)：对sequence中的item依次执行function(item)，将执行结果为True的item组成一个List/String/Tuple（取决于sequence的类型）返回.