AC自己主动机的模板题。因为输入的字符串中的字符不保证全为小写字母。所以范围应该在130之前,而前31位字符是不可能出如今字符串的(不懂得查下ACSII表即可了)。所以仅仅须要开的结点数组大小为130足够了。假设开256就会内存超限。

119087752014-10-19 10:45:38Accepted2896250MS29596KG++KinderRiven

输入仅仅有一组,所以不用操心超时的问题。

#include<queue>
#include<cstdio>
#include<vector>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn = 111111;
const int max_size = 130;
const int maxd = 222;
vector<int>G[1111];
struct Trie{
int next[maxn][max_size];
int fail[maxn];
int val[maxn];
int sz;
int root;
int index(char e){
return e - 31;
}
void init(){
sz = 0;
root = newnode();
}
int newnode(){
val[sz] = 0;
memset(next[sz],-1,sizeof(next[sz]));
sz ++;
return sz - 1;
}
void insert(char *str,int pos){
int L = strlen(str);
int u = root;
for(int i = 0; i < L; i++){
int e = index(str[i]);
if(next[u][e] == -1)
next[u][e] = newnode();
u = next[u][e];
}
val[u] = pos;
//printf("%d %d\n",u,pos);
}
void build(){ //建立失配边
fail[root] = root;
queue<int>q;
for(int i = 0; i < max_size; i++){
if(next[root][i] == -1)
next[root][i] = root;
else{
fail[next[root][i]] = root;
q.push(next[root][i]);
}
}
while(!q.empty()){
int now = q.front(); q.pop();
for(int i = 0; i < max_size; i++){
if(next[now][i] == -1)
next[now][i] = next[fail[now]][i];
else{
fail[next[now][i]] = next[fail[now]][i];
q.push(next[now][i]);
}
}
}
}
void count(char *str,int pos){
int L = strlen(str);
int u = root;
for(int i = 0; i < L; i++){
int e = index(str[i]);
u = next[u][e];
int temp = u;
while(temp != root){
if(val[temp] != 0)
G[pos].push_back(val[temp]);
temp = fail[temp];
}
}
return;
}
};
Trie ac;
int main(){
int n,m;
ac.init();
scanf("%d",&n);
for(int i = 1; i <= n; i++){
char str[maxd];
scanf("%s",str);
ac.insert(str,i);
}
//printf("%d\n",ac.sz);
ac.build();
scanf("%d",&m);
for(int i = 1; i <= m; i++){
char str[maxn];
scanf("%s",str);
ac.count(str,i);
}
int cnt = 0;
for(int i = 1; i <= m; i++)if(G[i].size()){
sort(G[i].begin(),G[i].end());
cnt ++;
printf("web %d:",i);
for(int j = 0; j < G[i].size(); j++)
printf(" %d",G[i][j]);
printf("\n");
}
printf("total: %d\n",cnt);
}

05-11 22:00