【CF527C】Glass Carving

题面

洛谷

题解

因为横着切与纵切无关

所以开\(set\)维护横着的最大值和纵着的最大值即可

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <set>
using namespace std;
inline int gi() {
register int data = 0, w = 1;
register char ch = 0;
while (!isdigit(ch) && ch != '-') ch = getchar();
if (ch == '-') w = -1, ch = getchar();
while (isdigit(ch)) data = 10 * data + ch - '0', ch = getchar();
return w * data;
}
typedef long long ll;
int W, H, N;
set<ll> cx, cy;
multiset<ll> x, y;
multiset<ll> :: iterator ite; int main() {
W = gi(), H = gi(), N = gi();
x.insert(W), y.insert(H);
cx.insert(0), cx.insert(W);
cy.insert(0), cy.insert(H);
for (int i = 1; i <= N; i++) {
char ch[5]; scanf("%s", ch);
int t = gi();
if (ch[0] == 'H') {
cy.insert(t); ite = cy.find(t); --ite;
ll l = *ite; ++ite; ++ite;
ll r = *ite;
ite = y.find(r - l);
y.erase(ite); y.insert(r - t); y.insert(t - l);
}
else {
cx.insert(t); ite = cx.find(t); --ite;
ll l = *ite; ++ite; ++ite;
ll r = *ite;
ite = x.find(r - l);
x.erase(ite); x.insert(r - t); x.insert(t - l);
}
ite = x.end(); --ite;
ll l = *ite;
ite = y.end(); --ite;
printf("%I64d\n", l * (*ite));
}
return 0;
}
05-10 19:05