传送门:地铁
思路:拆点,最短路;拆点比较复杂,所以对边进行最短路,spfa会tle,所以改用Dijkstra(优先队列优化)
/**************************************************************
Problem:
User: youmi
Language: C++
Result: Accepted
Time:
Memory:
****************************************************************/
//#pragma comment(linker, "/STACK:1024000000,1024000000")
//#include<bits/stdc++.h>
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <map>
#include <stack>
#include <set>
#include <sstream>
#include <cmath>
#include <queue>
#include <deque>
#include <string>
#include <vector>
#define zeros(a) memset(a,0,sizeof(a))
#define ones(a) memset(a,-1,sizeof(a))
#define sc(a) scanf("%d",&a)
#define sc2(a,b) scanf("%d%d",&a,&b)
#define sc3(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define scs(a) scanf("%s",a)
#define sclld(a) scanf("%I64d",&a)
#define pt(a) printf("%d\n",a)
#define ptlld(a) printf("%I64d\n",a)
#define rep(i,from,to) for(int i=from;i<=to;i++)
#define irep(i,to,from) for(int i=to;i>=from;i--)
#define Max(a,b) ((a)>(b)?(a):(b))
#define Min(a,b) ((a)<(b)?(a):(b))
#define lson (step<<1)
#define rson (lson+1)
#define eps 1e-6
#define oo (1e16)
#define TEST cout<<"*************************"<<endl
const double pi=*atan(1.0); using namespace std;
typedef long long ll;
template <class T> inline void read(T &n)
{
char c; int flag = ;
for (c = getchar(); !(c >= '' && c <= '' || c == '-'); c = getchar()); if (c == '-') flag = -, n = ; else n = c - '';
for (c = getchar(); c >= '' && c <= ''; c = getchar()) n = n * + c - ''; n *= flag;
}
ll Pow(ll base, ll n, ll mo)
{
if (n == ) return ;
if (n == ) return base % mo;
ll tmp = Pow(base, n >> , mo);
tmp = (ll)tmp * tmp % mo;
if (n & ) tmp = (ll)tmp * base % mo;
return tmp;
}
//*************************** int n,m;
const int maxn=+;
const ll mod=;
struct node
{
int v,c;
ll t,dis;
node(){}
node(int _v,int _c,ll _t,ll _dis)
{
v=_v,c=_c,t=_t,dis=_dis;
}
bool operator<(const node &a)const
{
if(dis==a.dis)
return t>a.t;
return dis>a.dis;
}
};
vector<node>vt[maxn];
void dijkstra()
{
ll ans=oo;
priority_queue<node>q;
for(int i=;i<vt[].size();i++)
{
vt[][i].dis=vt[][i].t;
if(vt[][i].v==n)
ans=min(ans,vt[][i].dis);
q.push(vt[][i]);
}
while(!q.empty())
{
node cur=q.top();
q.pop();
for(int i=;i<vt[cur.v].size();i++)
{
node temp=vt[cur.v][i];
if(temp.dis>cur.dis+temp.t+abs(cur.c-temp.c))
{
temp.dis=cur.dis+temp.t+abs(cur.c-temp.c);
if(temp.v==n)
ans=min(ans,temp.dis);
vt[cur.v][i]=temp;//非常重要,不要忘了这一步
q.push(temp);
}
}
}
printf("%lld\n",ans);
}
int main()
{
#ifndef ONLINE_JUDGE
//freopen("in.txt","r",stdin);
#endif
while(~sc2(n,m))
{
int a,b,c;
ll t;
for(int i=;i<=n;i++)
vt[i].clear();
rep(i,,m)
{
sc3(a,b,c);
scanf("%lld",&t);
vt[a].push_back(node(b,c,t,oo));
vt[b].push_back(node(a,c,t,oo));
}
dijkstra();
}
}