bzoj 4822: [Cqoi2017]老C的任务

4822: [Cqoi2017]老C的任务

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#include <iostream>

#include <cstdio>

#include <cstring>

#include <algorithm>

using namespace std;

typedef long long ll;

const int N = 1e6+5;

inline int read() {

    char c=getchar(); int x=0,f=1;

    while(c<'0' || c>'9') {if(c=='-')f=-1; c=getchar();}

    while(c>='0' && c<='9') {x=x*10+c-'0'; c=getchar();}

    return x*f;

}

int n, Q, mp[N], tot, x1, y1, x2, y2; ll ans[N];

struct meow {

	int x, y, type, qid; ll v;

	bool operator <(const meow &a) const {return x == a.x ? type < a.type : x < a.x;}

} q[N];

namespace bit {

	int n; ll c[N];

	inline void add(int p, ll v) {for(; p<=n; p+=p&-p) c[p] += v;}

	inline ll sum(int p) {ll ans = 0; for(; p; p-=p&-p) ans += c[p]; return ans;}

}

int main() {

	freopen("in", "r", stdin);

	n = read(); Q = read();

	for(int i=1; i<=n; i++)

		mp[++mp[0]] = q[i].x = read(), mp[++mp[0]] = q[i].y = read(), q[i].v = read(), q[i].type = 0;

	tot = n;

	for(int i=1; i<=Q; i++) {

		mp[++mp[0]] = x1 = read()-1; mp[++mp[0]] = y1 = read()-1;

		mp[++mp[0]] = x2 = read();   mp[++mp[0]] = y2 = read();

		tot++; q[tot] = (meow){x1, y1, 1, i, 1LL};

		tot++; q[tot] = (meow){x2, y2, 1, i, 1LL};

		tot++; q[tot] = (meow){x2, y1, 1, i, -1LL};

		tot++; q[tot] = (meow){x1, y2, 1, i, -1LL};

	}

	sort(mp+1, mp+1+mp[0]); mp[0] = unique(mp+1, mp+1+mp[0]) - mp - 1;

	for(int i=1; i<=tot; i++) {

		q[i].x = lower_bound(mp+1, mp+1+mp[0], q[i].x) - mp;

		q[i].y = lower_bound(mp+1, mp+1+mp[0], q[i].y) - mp;

	}

	sort(q+1, q+1+tot);

	bit::n = mp[0];

	for(int i=1; i<=tot; i++) {

		if(q[i].type) ans[q[i].qid] += q[i].v * bit::sum(q[i].y);

		else bit::add(q[i].y, q[i].v);

	}

	for(int i=1; i<=Q; i++) printf("%lld\n", ans[i]);

}