为了学CDQ分治,从斜率dp和凸包开始做吧。。
代码就是维护一个凸包。利用递增的性质丢掉不合适的点。
http://www.cnblogs.com/Rlemon/p/3184899.html
代码学的上面 很模板
#include <cstdio>
#include <algorithm> using namespace std;
//typedef long long LL; struct Point{
int x,y;
Point (int _x=,int _y=):x(_x),y(_y){}
Point operator - (const Point &rhs) const
{
return Point(x-rhs.x,y-rhs.y);
}
};
typedef Point Vector;
inline int Cross(const Vector &u,const Vector &v)
{
return u.x*v.y - u.y*v.x;
} const int maxn = 5e5+;
int N,M;
int sum[maxn],save[maxn];
int dp[maxn];
struct dequeue{
Point q[maxn];
int head,tail;
void init()
{
head = ;tail = ;
//q[head].x = 0;q[head].y = 0;
}
void push(const Point &u)
{
while(head < tail && Cross(q[tail]-q[tail-],u-q[tail])<=) tail--;
q[++tail] = u;
}
Point pop(const int &k)
{
while(head < tail && k*q[head].x+q[head].y >= k*q[head+].x + q[head+].y) head++;
//printf("head:%d x:%d y:%d\n",head,q[head].x,q[head].y);
return q[head];
}
}H; int main()
{
//freopen("input.txt","r",stdin);
while(~scanf("%d%d",&N,&M))
{
sum[] = ;
for(int i=;i<=N;i++)
{
scanf("%d",&save[i]);
sum[i] = sum[i-]+save[i];
}
H.init();
H.push(Point(,));
dp[] = ;
for(int i=;i<=N;i++)
{
int k = -*sum[i];
Point u = H.pop(k);
//printf("i:%d k:%d u.x:%d u.y:%d\n",i,k,u.x,u.y);
dp[i] = u.x*k + u.y + sum[i]*sum[i] + M;
H.push(Point(sum[i],dp[i]+sum[i]*sum[i]));
//printf("push:%d %d\n",sum[i],dp[i]+sum[i]*sum[i]);
}
printf("%d\n",dp[N]);
}
}