语法:

JsonPath

描述

$

根节点

@

当前节点

.or[]

子节点

..

选择所有符合条件的节点

*

所有节点

[]

迭代器标示,如数组下标

[,]

支持迭代器中做多选

[start:end:step]

数组切片运算符

?()

支持过滤操作

()

支持表达式计算

 

需要的jar包:

commons-lang-2.6.jar
json-path-0.8.1.jar
json-smart-1.1.1.jar

对于如下的json,通过实例介绍JsonPath的使用

{ "store": {
"book": [
{ "category": "reference",
"author": "Nigel Rees",
"title": "Sayings of the Century",
"price": 8.95
},
{ "category": "fiction",
"author": "Evelyn Waugh",
"title": "Sword of Honour",
"price": 12.99,
"isbn": "0-553-21311-3"
}
],
"bicycle": {
"color": "red",
"price": 19.95
}
}
}

代码:

private static void jsonPathTest() {
JSONObject json = jsonTest();//调用自定义的jsonTest()方法获得json对象,生成上面的json //输出book[0]的author值
String author = JsonPath.read(json, "$.store.book[0].author"); //输出全部author的值,使用Iterator迭代
List<String> authors = JsonPath.read(json, "$.store.book[*].author"); //输出book[*]中category == 'reference'的book
List<Object> books = JsonPath.read(json, "$.store.book[?(@.category == 'reference')]"); //输出book[*]中price>10的book
List<Object> books = JsonPath.read(json, "$.store.book[?(@.price>10)]"); //输出book[*]中含有isbn元素的book
List<Object> books = JsonPath.read(json, "$.store.book[?(@.isbn)]"); //输出该json中所有price的值
List<Double> prices = JsonPath.read(json, "$..price"); //可以提前编辑一个路径,并多次使用它
JsonPath path = JsonPath.compile("$.store.book[*]");
List<Object> books = path.read(json);
}
05-07 15:48