题目链接

http://acm.hznu.edu.cn/OJ/problem.php?id=2264

思路

从终点往起点走 然后每次更新状态

因为要满足 最短路线

所以其实 只能是 往左走,往下走 或者 往下一层走

AC代码

#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <cmath>
#include <climits>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>
#include <iomanip>
#include <limits> #define CLR(a) memset(a, 0, sizeof(a))
#define pb push_back using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef pair<string, int> psi;
typedef pair<string, string> pss; const double PI = 3.14159265358979323846264338327;
const double E = exp(1);
const double eps = 1e-30; const int INF = 0x3f3f3f3f;
const int maxn = 1e2 + 5;
const int MOD = 1e9 + 7; int G[maxn][maxn][maxn];
int dp[maxn][maxn][maxn]; int main()
{
int n, m, h;
while (~scanf("%d%d%d", &n, &m, &h))
{
CLR(G);
for (int k = 1; k <= h; k++)
{
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
scanf("%d", &G[k][i][j]);
}
}
}
CLR(dp);
for (int k = h; k >= 1; k--)
{
for (int i = 1; i <= n; i++)
{
for (int j = m; j >= 1; j--)
{
dp[k][i][j] = max(max(dp[k + 1][i][j], dp[k][i - 1][j]), dp[k][i][j + 1]) + G[k][i][j];
}
}
}
cout << dp[1][n][1] << endl;
}
}
05-11 18:18