题目链接
http://acm.hznu.edu.cn/OJ/problem.php?id=2264
思路
从终点往起点走 然后每次更新状态
因为要满足 最短路线
所以其实 只能是 往左走,往下走 或者 往下一层走
AC代码
#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <cmath>
#include <climits>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>
#include <iomanip>
#include <limits>
#define CLR(a) memset(a, 0, sizeof(a))
#define pb push_back
using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef pair<string, int> psi;
typedef pair<string, string> pss;
const double PI = 3.14159265358979323846264338327;
const double E = exp(1);
const double eps = 1e-30;
const int INF = 0x3f3f3f3f;
const int maxn = 1e2 + 5;
const int MOD = 1e9 + 7;
int G[maxn][maxn][maxn];
int dp[maxn][maxn][maxn];
int main()
{
int n, m, h;
while (~scanf("%d%d%d", &n, &m, &h))
{
CLR(G);
for (int k = 1; k <= h; k++)
{
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
scanf("%d", &G[k][i][j]);
}
}
}
CLR(dp);
for (int k = h; k >= 1; k--)
{
for (int i = 1; i <= n; i++)
{
for (int j = m; j >= 1; j--)
{
dp[k][i][j] = max(max(dp[k + 1][i][j], dp[k][i - 1][j]), dp[k][i][j + 1]) + G[k][i][j];
}
}
}
cout << dp[1][n][1] << endl;
}
}