JS去掉所有select标签的disabled属性

html代码

1. <form role="form" action="/save_element/" method="post" id="obj_form" onsubmit="return select_disable()">
   
2. {% csrf_token %}
   
3.     <select class="form-control" name="obj_find_type" id="{{ elements.type_select_id }}" style="border: none;outline:medium;width: 250px;" disabled>
   
4.         {% for find_type in find_type_list %}
   
5.              {% if elements.type == find_type %}
   
6.                 <option value = {{ find_type }} selected="selected" >{{ find_type }}</option>
   
7.              {% else %}
   
8.                 <option value = {{ find_type }}>{{ find_type }}</option>
   
9.              {% endif %}
   
10.         {% endfor %}
    
11.     </select>
    
12.     <div class="well well-sm" style="text-align:center">
    
13.         <button id="do_save" type="submit" class="btn btn-primary btn-flat m-b-10 m-l-5">保存</button>
    
14.     </div>
    
15. </form>

想要把form里面的所有select 标签的disabled 都去掉。
JS代码如下：

1. <script type="text/javascript">
   
2. 
   
3. function select_disable(){
   
4.     //先获取所有的select标签对象
   
5.     var select_name = document.getElementsByTagName("select");
   
6.     //逐个遍历select
   
7.     for(var i=0; i<select_name.length; i++){
   
8.         //select_name是一个数组
   
9.         //获取select的id值
   
10.         var select_id = select_name[i].id;
    
11.         //使用id值操作标签属性disabled
    
12.         $("#" + select_id).attr("disabled",false);
    
13.     }
    
14. }
    
15. 
    
16. </script>