上篇:
上篇中,udtf函数,只有为一行输入,一行输出。udtf是可以一行输入,多行输出的。
简述下需求:
输入开始时间,结束时间,返回每个小时的时长
直接上代码:
package com.venn.udtf; import org.apache.hadoop.hive.ql.exec.UDFArgumentException;
import org.apache.hadoop.hive.ql.exec.UDFArgumentLengthException;
import org.apache.hadoop.hive.ql.metadata.HiveException;
import org.apache.hadoop.hive.ql.udf.generic.GenericUDTF;
import org.apache.hadoop.hive.serde2.objectinspector.ObjectInspector;
import org.apache.hadoop.hive.serde2.objectinspector.ObjectInspectorFactory;
import org.apache.hadoop.hive.serde2.objectinspector.StructObjectInspector;
import org.apache.hadoop.hive.serde2.objectinspector.primitive.PrimitiveObjectInspectorFactory; import java.util.ArrayList; /**
* Created by venn on 5/20/2018.
* SplitHour : split hour
*/
public class SplitHour extends GenericUDTF { /**
* add the column name
* @param args
* @return
* @throws UDFArgumentException
*/
@Override
public StructObjectInspector initialize(ObjectInspector[] args) throws UDFArgumentException {
if (args.length != 1) {
throw new UDFArgumentLengthException("ExplodeMap takes only one argument");
}
if (args[0].getCategory() != ObjectInspector.Category.PRIMITIVE) {
throw new UDFArgumentException("ExplodeMap takes string as a parameter");
} ArrayList<String> fieldNames = new ArrayList<String>();
ArrayList<ObjectInspector> fieldOIs = new ArrayList<ObjectInspector>();
fieldNames.add("begintime");
fieldOIs.add(PrimitiveObjectInspectorFactory.javaStringObjectInspector);
fieldNames.add("endtime");
fieldOIs.add(PrimitiveObjectInspectorFactory.javaStringObjectInspector);
fieldNames.add("hour");
fieldOIs.add(PrimitiveObjectInspectorFactory.javaStringObjectInspector);
fieldNames.add("seconds");
fieldOIs.add(PrimitiveObjectInspectorFactory.javaStringObjectInspector); return ObjectInspectorFactory.getStandardStructObjectInspector(fieldNames, fieldOIs);
} /**
* process the column
* @param objects
* @throws HiveException
*/
public void process(Object[] objects) throws HiveException { String [] input = objects[0].toString().split(",");
// 2018-06-06 10:25:35
String beginTime = input[0];
String endTime = input[1]; String[] result = new String[4];
result[0] = beginTime;
result[1] = endTime; // begintime
int bhour = Integer.parseInt(beginTime.substring(11, 13));
int bmin = Integer.parseInt(beginTime.substring(14, 16));
int bsecond = Integer.parseInt(beginTime.substring(17, 19));
// endtime
int ehour = Integer.parseInt(endTime.substring(11, 13));
int emin = Integer.parseInt(endTime.substring(14, 16));
int esecond = Integer.parseInt(endTime.substring(17, 19)); // 1.if begin hour equal end hour, second is : (emin - bmin) * 60 + (esecond - bsecond)
if (bhour == ehour) {
result[2] = String.valueOf(bhour);
result[3] = String.valueOf((emin - bmin) * 60 + (esecond - bsecond));
forward(result);
return;
} boolean flag = true;
//TODO 待优化,先输出第一个循环的时长,再循环后面的就不用判断
while (bhour != ehour) {
result[2] = String.valueOf(bhour); if(flag){
flag = false;
// 2. if begintime hour != endtime, the first hour, second is : 3600 - bmin * 60 - bsecond
result[3] = String.valueOf(3600 - bmin * 60 - bsecond);
}else {
// 3. next hour is 3600
result[3] = String.valueOf();
}
bhour += 1;
// 输出到hive
forward(result);
} result[2] = String.valueOf(bhour);
// 4. the end hour is : emin * 60 + esecond
result[3] = String.valueOf( emin * 60 + esecond);
forward(result); } public void close() throws HiveException { } }
udtf 函数介绍参加上篇
使用方式见上篇
样例:
hive> select split_hour( concat(begintime,',',endtime)) from viewlog where log_date= limit ;
OK
begintime endtime hour seconds
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
-- :: -- ::
2018-04-01 12:15:07 2018-04-01 12:15:11 12 4
2018-04-01 06:53:40 2018-04-01 07:02:09 6 380
2018-04-01 06:53:40 2018-04-01 07:02:09 7 129
Time taken: 2.238 seconds, Fetched: row(s)
搞定