//原始方法://val list=List("abc","bcd","cde")scala> list.sortWith( (s,t) => s.compareTo(t) <0 )res1: List[String] = List(abc,bcd,cde)//匿名方法:scala> list.sortWith( _.compareTo(_) <0 )res2: List[String] = List(abc,bcd,cde)//上述为字典序递增,若递减则改'<'为'>'即可